Question

Hello, I tried 3.1e13 and 3.1e14

In the Bohr model of the hydrogen atom, the electron in the n = 11 level moves in a circular orbit of radius 6.40 x 10-9 m around the proton. Assume the orbital angular momentum of the electron is equal to 11h/21. (a) Calculate the orbital speed of the electron. 1.99e5 m/s (b) Calculate the kinetic energy of the electron. 1.8e-20 j (c) Calculate the angular frequency of the electron's motion. 3.1e14 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. rad/s

but they says it wrong!

Answer 1

c] angular frequency w = v/r = 1.99e5/6.4e-9

= 3.11e13 rad/s

By other method, angular momentum = I*w

11h/2pi = mr^2*w

w = [11h/2pi]/(mr^2)

= [11*6.626e-34/(2pi)]/[9.1e-31*6.4e-9^2]

= 3.11e13 rad/s answer