Question

Design a Logical Topology with the following constraints: Material Constraints: 2x 24-Port, Layer 3 Network Switches 1x Edge Router (connected out to the local LAN, the external RV215W LAN, and the WAN - 3 total connections) 2x Wireless Access Points 1x Cisco RV215W (connected to the edge router to allow LAN communication from another building) 30 total network devices (these will determine your total subnets/VLANs and subnet scopes): 10 VoIP phones 4 Executive computers 2 Administration computers 2 Finance computers 3 Printers 2 IT computers 2 Servers 5 network transport devices (listed above) The Cisco RV215W Logical Topology: 1. Use the image-editing tool of choice (a picture of pen-and-paper is fine) 2. Create a logical topology of the network you described above 3. Remember: Physical location is irrelevant in a logical topology, only how our devices are connected (VLAN's, Subnets, connection types, etc.) need to be included. 4. You need to include the following in your topology: All device IP addresses All port numbers used (most important on switches and routers) Give all devices appropriate host names (excluding the VoIP phones)

Task 2. Create a subnet scheme based upon the above functions and devices per function.  

**(Use a Private Class C: 192.168.100.x)**

1. Document your subnet scheme as a list containing the Department/Function name, Net ID, host range, and Broadcast ID for each.
2. Don't forget to allocate an additional 192.168.x.x /30 for your router-to-router (Edge Router to RV215W) connection and identify that in your list. This subnet does not need to fall within the listed IP constraint above.

Answer 1

Major Network: 192.168.100.0/24
Available IP addresses in major network: 254
Number of IP addresses needed: 30
Available IP addresses in allocated subnets: 40

Subnet Name	Needed Size	Allocated Size	Address	Mask	Dec Mask	Assignable Range	Broadcast
VoIP phones	10	14	192.168.100.0	/28	255.255.255.240	192.168.100.1 - 192.168.100.14	192.168.100.15
network	5	6	192.168.100.16	/29	255.255.255.248	192.168.100.17 - 192.168.100.22	192.168.100.23
Executive computers	4	6	192.168.100.24	/29	255.255.255.248	192.168.100.25 - 192.168.100.30	192.168.100.31
Printers	3	6	192.168.100.32	/29	255.255.255.248	192.168.100.33 - 192.168.100.38	192.168.100.39
Administration computers	2	2	192.168.100.40	/30	255.255.255.252	192.168.100.41 - 192.168.100.42	192.168.100.43
Finance computers	2	2	192.168.100.44	/30	255.255.255.252	192.168.100.45 - 192.168.100.46	192.168.100.47
IT computers	2	2	192.168.100.48	/30	255.255.255.252	192.168.100.49 - 192.168.100.50	192.168.100.51
Servers	2	2	192.168.100.52	/30	255.255.255.252	192.168.100.53 - 192.168.100.54	192.168.100.55

Router
********

Major Network: 192.168.100.100/30
Available IP addresses in major network: 2
Number of IP addresses needed: 2
Available IP addresses in allocated subnets: 2

Subnet Name	Needed Size	Allocated Size	Address	Mask	Dec Mask	Assignable Range	Broadcast
Router	2	2	192.168.100.100	/30	255.255.255.252	192.168.100.101 - 192.168.100.102	192.168.100.103

if you have any doubt then please ask me without any hesitation in the comment section below , if you like my answer then please thumbs up for the answer , before giving thumbs down please discuss the question it may possible that we may understand the question different way and we can edit and change the answers if you argue, thanks :)