Question

How many milliliters of 0.0360 M EDTA are required to react with 50.0 mL of 0.0110 M Cu2+? volume: mL How many milliliters of 0.0360 M EDTA are required to react with 50.0 mL of 0.0110 M Sc3+? volume: mL

Answer 1

(a) Cu²⁺

volume : 15.3 mL

(b) Sc³⁺

volume : 15.3 mL

Explanation

(a) concentration Cu²⁺ = 0.0110 M

volume Cu²⁺ = 50.0 mL

moles Cu²⁺ = (concentration Cu²⁺) * (volume Cu²⁺)

moles Cu²⁺ = (0.0110 M) * (50.0 mL)

moles Cu²⁺ = 0.55 mmol

moles EDTA required = moles Cu²⁺

moles EDTA required = 0.55 mmol

volume EDTA required = (moles EDTA required) / (concentration EDTA)

volume EDTA required = (0.55 mmol) / (0.0360 M)

volume EDTA required = 15.3 mL

(b) concentration Sc³⁺ = 0.0110 M

volume Sc³⁺ = 50.0 mL

moles Sc³⁺ = (concentration Sc³⁺) * (volume Sc³⁺)

moles Sc³⁺ = (0.0110 M) * (50.0 mL)

moles Sc³⁺ = 0.55 mmol

moles EDTA required = moles Sc³⁺

moles EDTA required = 0.55 mmol

volume EDTA required = (moles EDTA required) / (concentration EDTA)

volume EDTA required = (0.55 mmol) / (0.0360 M)

volume EDTA required = 15.3 mL