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MgO(s) + 2HCl(aq) → 2Cl(aq) + Mg(aq) + H2O(l): AH = A student added 0.250 g of MgO(s) to 45.0 mL HCI@ 22.0C. The temp of the

Specific heat = 4.18 J/g*C
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Answer #1

Number of moles of Mgo = mass/mol.wt. = 0.250 g/(40.30 g/mol) = 0.006203 mol Mass of HCl = volume * density = 45.0 mL * 1.05

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Specific heat = 4.18 J/g*C MgO(s) + 2HCl(aq) → 2Cl(aq) + Mg(aq) + H2O(l): AH = A student added 0.250 g of Mg...
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