Mass of U-235 needed = 56 kg = 56000 g
Molar Mass of U-235 = 235.0439 g/mol
Moles of U-235 needed = Mass/ Molar Mass = 56000 g / (235.0439 g/mol)=238.253 mol
1 mole of UF6 give 1 mole U-235. Thus moles of UF6 needed = 238.253 mol
Molar Mass of UF6 = 235.0439 + 6 * 18.9984 g/mol = 349.0343 g/mol
Thus, weight of UF6 needed = Moles * Molar Mass = 238.253 mol * 349.0343 g/mol = 83158.47 g = 83.158 kg
Thus, the amount of UF6 needed is 83.158 kg.
2. 23 U is a fissile isotope of uranium, used in the atomic bomb dropped on Hiroshima in 1945. The critical mass is...
. (_92^235)U is a fissile isotope of uranium, used in the atomic bomb dropped on Hiroshima in 1945. The critical mass is 56 kg. The primary isotope is not fissile and had to be removed by a process which required synthesis of UF6, a gas. How much 235UF6 was required to produce a critical mass of the element? [Molar masses: U, 235.0439 g; F, 18.9984 g]