Question

Please show all work on now all work and explain your reasoning carefully for all questions in order to maximize the possibility of partial credit The spring shown in the diagram below is compressed 50cm and used to launch a 95kg physics student seated on a 5kg sled. Friction on the track is 4 0.15 on the shaded portions and negligible for the solid portions. The track's valley and hill consist of circular shaped segments of radius "R". a. What is the maximum height mar from which the car can start so as not to fly off the track when going over the hill? (Give your answer as a multiple of "R".) (15pts) - 80.000 N/m = 100 kg 10 m 130° b. Now let R = 8m and h = max which you found in part (a). This means the student and the sled will reach the end of the last portion of inclined track and fly off of the end. If the student and sled are caught by a hanging cart of mass 600kg, as shown below, how high in terms of the angle "0" will the cart containing the student and sled swing? (18pts) - 80.000 N/m & m= 100 kg 25° 130

Answer 1

insven Ax= 0.5 M = 95 kg = 5ke H=0.15M 30 R k= 80 Nm a) over the hill, if we be speed teen (mt) L = ( M g-N NCO for V to hand max value 202= GR- NSW from Corises valatim of energy from point A to point 8. Kax +- (M+mg/10+) = (M+m) + Mg( matom)g cosas y do + KAZ' + (Mumy (loth) - (+) 12. Al Mima X10 XC01239 +u+miga fox.5+ (0x918110th 100X9.9XR + 5X1X .8x10x2114 + 100X0.8 XR OR = 10 +950/10 +) = 490 R+ 3145.8 + (loth) = 1470R+314518-10 3135% +1470R 48 430 human= 3-2 + 1,50 - 10 = (1-5R- 68) b) Now by conservation of evorgy from B to c wen (M=m) 202 + ( +miga = NECMAWO CABOX + (M+m) +m+wiga = 80X9-8x8 + 110**** = -5*100*9.841345 + X XV + MB-SR: 7 V = $7.66 VE 6.4 m/s Now long momentam Conservalu TODXV - T V ! We'= 0.877 m Now by conleuneko tangy 11700) X-4772 = 700*9.84Y 4 AY = '039 So cong = (1- 1034 where Lis length of shing & e co' (1-1939)