Question

an ocean on earth were stuck by a comet nucleus a kilometer across? What physical affects would occur to earth?Assume that the comet has the same density as water ice and that it strikes the Earth with a velocity equal to the orbital velocity of Earth: what amount of energy would be released? Compare this amount to the energy needed by a 70 kg human to climb the 10 m high or so room.

Answer 1

radius of comat - 1km. density of comet = density of wat Ice = 19/m3 o 103 kg/m3 orbital relocity of earth = 0 0 0 0 0 0 UU M- man ay earth Ra radius of earth v=18.67X10'X 6.0X1024|'12 64*106 ) u= 2.98% 105 misl Impact energy of comat mv2 a \f. Vol), v2 = - m3 = amuning spherical comel m= fival 04xnx (1900m) 3 x 103 kg m 3 4,24 x1017 kg 1 Finthian *4,24 xlobe by X (2.987109j2 1. Eine 6.3x1021 Joule 2 Energy needed for man to climb tom. £= mgh = 70 kg * 9.8 x 10 z 6,86 X103J

The energy impact in so so huge. Eman Eimpact -6.86*23 J - 6.3810215 mot Eimpact = 9.18x1017x Emen ,