Question 12 1 pts Use the following thermochemical data to determine which of the following is the most exothermic...
7. Use the thermochemical equation below to find the AH of the following: CH.(g) + H2O(g) → CO(g) + 3 H2(g) AH = +206 kJ 2CH(g) + 2H2O(g)} 2 CO(g) + 6H2(g) AH CO(g) + 3 H2(g) → CH(g) + H2O(g) AH AH 2 CO(g) + 6 H2(g) → 2 CH:(g) + 2 H2O(g)
Please write clearly and use significant figures. thanks in advance 6. Use the following thermochemical equation for the synthesis of ammonia. N2(g) + 3 H2(g) → 2 NH3(g) AH=-91.8 kJ Rewrite the thermochemical equation to show 3 moles of hydrogen being produced? Rewrite the thermochemical equation to show 6 moles of hydrogen being produced? Rewrite the thermochemical equation to show the production of 6 moles of NH3 produced? 7. Use the thermochemical equation below to find the AH of the...
Use Hess's law and the following data CH4(g) + 2O2(g) → CO2(g) + 2 H2O(g) AH° = -802 kJ mol-1 CH4(8) + CO2(g) —> 2CO(g) + 2 H2(g) AFH° = +247 kJ mol-1 CH4(g) + H2O(g) –> CO(g) + 3H2(g) AFH° = +206 kJ mol-1 to determine A.Hº for the following reaction, an important source of hydrogen gas CH4(8) + +02(8) — CO(g) + 2 H2(8)
6. Use the following thermochemical equation for the synthesis of ammonia N2(g) + 3 H2(g) → 2 NH3(g) AH = -91.8 kJ Rewrite the thermochemical equation to show 3 moles of hydrogen being produced? Rewrite the thermochemical equation to show 6 moles of hydrogen being produced? Rewrite the thermochemical equation to show the production of 6 moles of NH3 produced? 7. Use the thermochemical equation below to find the AH of the following: CH_(g) + H2O(g) → CO(g) + 3...
#1 #2 #3 Classify each of the following processes as exothermic or endothermic. 1. The dissolution of NaOH in water causes the water to become warm. 2.When an instant ice pack is activated, it becomes cold to the touch. 3.In the combustion of propane, a bright flame is produced 4.2H2(g) + O2(g) → 2H2O(g) + 483 kJ/mol How much energy is required to produce 4.67 g. C6H1206(s)? (The molar mass of C6H1206 is 180.16 g/mol.) |6C02(g) + 6H2O(g) + 2801...
Question 10 1 pts Consider the equilibrium: CH, (g) + H2O(g) + 206 kJ CO(g) + 3H2(g). Which of the following disturbances will NOT cause the system to shift to the right to reestablish equilibrium? The volume decreases. The temperature increases. The partial pressure of CO decreases. All of these will cause the system to shift to the right. • The partial pressure of CH4 increases.
10. Given the thermochemical data below, what is the change in enthalpy when 10.0 g of H, are reacted? N; (g) + 3H2(g) → 2NH, (g): AH = -91.2 kJ (A) -452 kJ (B) +452 kJ (C) -151 kJ (D) -1357 kJ 11. Which of the following is NOT a state function? 1. Heat 2. Change in enthalpy 3. Change in internal energy 4. Change in pressure (A) 1 only (B) 2 only (C) 2 and 3 (D) 1 and...
Question 8 10 pts Methane gas reacts with water vapor to produce a mixture of carbon monoxide and hydrogen, according to the balanced equation below. CH4(8) + H2O(g) → CO(g) + 3H2(8) AH® for the reaction is +206.1 kJ/mol, while ASⓇ is +215 J/Komol. At what temperature (in °C) does this reaction become spontaneous?
1.(3pts) Use the following data to determine the AHıxn of 2 C3H12O(l) + 15 O2(g) ----> 10 CO2(g) + 12 H2O(1) Substance AH(kJ/mol) Substance AH(kJ/mol) Data: CzH.(g) CH,OH(1) C.H.0(1) C6H40(1) H2O(g) CO(g) O2(g) 20.9 -239.0 -277.0 -316.0 -241.82 -110.53 C3H2(g) CHOH(9) CH 20(1) CH;60(1) H2O(1) -104.0 -201.0 -298.6 -340.0 -285.83 -393.51 CO2 N (8) 2.(2pts) If you are given 148,0 g O2(g) and a sufficient amount of the other reactant, calculate the heat associated with reaction in problem 1 and...
Review Problem 6.086 Given the following thermochemical equations, 2Cu + S(s) - Cu2S(s) AH° = -79.5 kJ S(s) + O2(g) → SO2(9) AH = -297 kJ Cu2S(s) + 202(g) → 2CụO(s) + SO2(g) AH° = -527.5 kJ calculate the standard enthalpy of formation (in kilojoules per mole) of Cuo(s). AH°(Cuo(s)) - kJ/mol The number of significant digits is set to 3; the tolerance is +/-2% Show Work is REQUIRED for this question: Open Show Work Review Problem 6.087 Given the...