Question

7. Use the thermochemical equation below to find the AH of the following: CH.(g) + H2O(g) → CO(g) + 3 H2(g) AH = +206 kJ 2CH(g) + 2H2O(g)} 2 CO(g) + 6H2(g) AH CO(g) + 3 H2(g) → CH(g) + H2O(g) AH AH 2 CO(g) + 6 H2(g) → 2 CH:(g) + 2 H2O(g)

Answer 1

e9@CHA (%) + H20 (g) → colg) + 3 H2(0), AH = +206 kJ. according to the above. Chemical equations : Imole of erygreacts with Imole of H₂O(g) Producing . I mole of colg) and 3 mol of H₂(g). In this reaction, enthalpy Change is AH = +206 kJ.. (+) ve sign denotes that this reaction is endothermie. It absorbos heat energy of 206ks for the reaction to be occured Completely. ... ( 2 CH 3) + 2H, 0 (8 > 2_ce (8) + 6 H2 (8), AH-6) A1 2 3 This reaction equation is obtained if we multiply the eq. ① by 2 : oh becomes (2 x 206) KJ = (+) 412 KJ ... . 412 kg heat is to be absorbed, then amol of cha react with 2 mol of tho resulting 2 mol of co and 6 mol of Hq.

1 (6) colg) + 3H2 (8) CHA ) + H2O (@) ; AH = (–206 KJ This equation is obtained if we reverse the eq.... Ah for this read becomes =) 206 kJ because of the law of Lavoisier and Laplace. [the heat change for a reaction in forward direction is aequal in the magnitude but opposite in sign... for the backward reaction (reverse reaction)] © 20019 + 6H2(8) 2ety (g) +2H20 (1); 4H=(-)412 KJ This equation is obtained if we multiply the equation of(b) by 2 AH for this reaction becomes to : 2x6) 206 KJ = 641'2 KJ This equation is also obtained by reversing the equation of (a) and at becomes. (-) 412 KJ according to the Law of the Lavoisier and Laplace. 'AH = (+)412 KJ @ 2CH4(8) + 2H20 (3) 72004)+ 6Hz (8) (b) Co (g) + 3H₂(8) > CHA (8) + H₂O (9) ©.200(8) + 6Hz (+2CH2C%) + 2+40 (3) AH 26-)206 KJ AH 21-1412 KJ