Question

Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or better not answer it if not then, really appreciate it, thank you.

2 The manager of a bank wanted to know whether the four tellers serve, on average, the same number of customers per hour. A r

0 0
Add a comment Improve this question Transcribed image text
Answer #1

(a)

Test for Equal Variances: No. of Customers versus Teller

95% Bonferroni confidence intervals for standard deviations

Teller N Lower StDev Upper
I 5 1.53911 2.91548 12.0956
II 6 2.00969 3.61939 12.0274
III 6 0.91238 1.64317 5.4603
IV 5 1.77460 3.36155 13.9462


Bartlett's Test (Normal Distribution)
Test statistic = 2.77, p-value = 0.428


Levene's Test (Any Continuous Distribution)
Test statistic = 1.07, p-value = 0.385
Since p-value>0.05 so we conclude that variances of observations corresponding 4 tellers are equal.

Test for Equal Variances for No. of Customers Bartletts Test Test Statistic 2,77 P-Value 0.428 Levenes Test Test Statistic

(b)

One-way ANOVA: No. of Customers versus Teller

Source DF SS MS F P
Teller 3 255.62 85.21 9.69 0.000
Error 18 158.20 8.79
Total 21 413.82

Since p-value<0.05 so the mean number of customers served per hour by each of these four tellers are not same.

(c)

Level N Mean StDev ------+---------+---------+---------+---
I 5 22.000 2.915 (-------*-------)
II 6 15.500 3.619 (------*-------)
III 6 14.500 1.643 (------*-------)
IV 5 21.600 3.362 (-------*-------)
------+---------+---------+---------+---
14.0 17.5 21.0 24.5

Pooled StDev = 2.965


Grouping Information Using Tukey Method

Teller N Mean Grouping
I 5 22.000 A
IV 5 21.600 A
II 6 15.500 B
III 6 14.500 B

Means that do not share a letter are significantly different.


Tukey 95% Simultaneous Confidence Intervals
All Pairwise Comparisons among Levels of Teller

Individual confidence level = 98.89%


Teller = I subtracted from:

Teller Lower Center Upper  
II -11.577 -6.500 -1.423
III -12.577 -7.500 -2.423  
IV -5.703 -0.400 4.903   
Since from the above C.I. s we see that C.I. for (Teller II-Teller I) does not contain zero hence Teller I and Teller II are significantly different.   


Teller = II subtracted from:

Teller Lower Center Upper
III -5.841 -1.000 3.841
IV 1.023 6.100 11.177
Since from the above C.I. s we see that C.I. for (Teller IV-Teller II) does not contain zero hence Teller IV and Teller II are significantly different.      


Teller = III subtracted from:

Teller Lower Center Upper  
IV 2.023 7.100 12.177
Since the C.I. for (Teller IV-Teller III) does not contain zero hence Teller IV and Teller III are significantly different.

Add a comment
Know the answer?
Add Answer to:
Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or be...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or be...

    Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or better not answer it if not then, really appreciate it, thank you. A consumer agency wanted to find out if the mean time taken for each of three brands of medicines to provide headache relief is the same. The first drug was administered to six patients, the second to four patients and the third to five patients. All were randomly administered. The...

  • Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or be...

    Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or better not answer it if not then, really appreciate it, thank you. experiment using 3 (a) The ANOVA table below shows the result of an randomized complete block design d.f. Source SS Treatment Block 90.917 18.167 2 Error 6 3.833 Total 11 112.917 = 0,05, test differences among Using (i) treatment means block means. (11) (40 marks) en (b) A mathematics teacher...

  • Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or be...

    Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or better not answer it if not then, really appreciate it, thank you. 5. (a) Explain briefly the difference between fixed effects model and random effects model in the one-way analysis of variance Give the hypothesis of random effects model in the one-way analysis of variance. (11 (20 marks) (b) Eight music videos were ranked by teenagers and their parents on style and...

  • Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or be...

    Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or better not answer it if not then, really appreciate it, thank you. 5 (a) An incomplete result of summarized in the analysis of variance table below. experiment using Latin square design is an Source of Degrees of Sum of Mean Variation Squares Freedom Squares Treatments 7 58.25 Rows 17.25 7 38.25 Columns Error 6.5 Total 7 State the size of the Latin...

  • Note: Answer the Question(s) by Using the TI-30XA (or other approved) Calculator. IMPORTANT: Make...

    Note: Answer the Question(s) by Using the TI-30XA (or other approved) Calculator. IMPORTANT: Make sure you carry all decimals until you reach your answer, then round to four decimals. 10 12 13 A consultant for a large university studied the number of hours per week freshmen watch TV versus the number of hours seniors do. The results of this study follow. Is there enough evidence to show the mean number of hours per week freshmen 15 watch TV is different...

  • please provide the output in R aov (hw labels) >summary (fit) > fit Df Sum Sq...

    please provide the output in R aov (hw labels) >summary (fit) > fit Df Sum Sq Mean Sq F value Pr(>F) 2 493.3 labels 246.7 5.763 0.0176 Residuals 12 513.6 42.8 Signif. codes: 0 0.001 0.01 0.05 0.1 1 12. For this problem, you will use R to conduct an ANOVA F-test. The R code from #11 should be useful for this problem. In #11, the dean only collected samples of size five from each engineering majors. Suppose he collects...

  • The mean arrival rate of flights at O’Hare Airport in marginal weather is 195 flights per...

    The mean arrival rate of flights at O’Hare Airport in marginal weather is 195 flights per hour. To increase arrivals, a new air traffic control procedure is implemented. a) State the Hypothesis to show there has been a significant increase in the mean number of arrivals per hour. b) To test the hypothesis, O’Hare Airport takes data on the next 30 days with marginal weather. The data appear in the Airport worksheet of the Hypothesis Tests HW data workbook on...

  • QUESTION 20 A local diner would like to see an increase in the number of customers...

    QUESTION 20 A local diner would like to see an increase in the number of customers over the lunch hour. Currently, they average 25 customers per day over the lunch hour. They decide to offer a special menu of lunch deals at reduced rates to try to bring in more customers. Following the introduction of the new special lunch menu, they track data over the course of 24 days and find a sample mean of 35.6 customers with a standard...

  • Please write in the answer clear. Will leave like if its correct . Age Gen Sibs Work Exercise Units Mom 18 M 1 20 10 15 6 17 F 3 0 7 15 14 23 M...

    Please write in the answer clear. Will leave like if its correct . Age Gen Sibs Work Exercise Units Mom 18 M 1 20 10 15 6 17 F 3 0 7 15 14 23 M 3 20 5 13 8 20 M 2 0 5 15 16 18 F 4 22 6 16 9 20 F 2 11 7 20 20 34 F 1 48 10 10 18 22 F 3 37 13 13 18 19 M 3 0...

  • please Answer question 9 and 10 Question 4 answer is : The distribution is not normally...

    please Answer question 9 and 10 Question 4 answer is : The distribution is not normally distributed. Question 6 answer is : 80% Question 7 answer is : 92% Question 8 answer is : 98% Question: Using the computer (Excel), answer the following 10 questions: Assessing Normality Many times in statistics it is necessary to see if a set of data values is approximately normally dis- tributed. There are special techniques that can be used. One technique is to draw...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT