In this experiment you will synthesize an alkene reacting an alcohol with acid.You will start with one of four possible alcohols: cycloheptanol, cyclohexanol, 1-methylcyclohexanol, 4-methylcyclohexanol, and 1-methylcyclopentanol. You will use C13 NMR to identify the nature of the starting material and product.
So basically, what is the starting material and product based on the compound that is being shown in the NMR. Which alcohol is unknown B and which alkene corresponds with it? And how did you get this answer? Please show your work
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Basically synthesis of the alkene from the mixture of alcohol and acid, we must undergo dehydration of alkene mechanism.
As per above C13 NMR interpretation after analyzing it is identified that the starting material will be cyclohexane or its derivatives that undergoes with the help of strong acid to dehydrate and results in cyclohexene along with water. Because in the C13 it's clearly mentioned MW 82.1 and it's for cyclohexene.
In this experiment you will synthesize an alkene reacting an alcohol with acid.You will start with one of four possible...
For the 13C NMR, determine the unknown: Unknown Answers: -cycloheptanol -1-methylcyclohexanol - cyclohexanol - cylopentanol -4-methycyclohexanol Unknown_B_CARBON-2.jar UK-B MW= 82.1 160.0 150.0 140.0 130.0 190.0 160.0 20.0 MOLO 170.0 110.0 100,0 70.0 90.0 0.0 0.0 0.0 0.0 0.0 20.0 100 177.2125 77,4207 77.0000 76.5793 25.1049 EILSU
Which unknown from the list represents the NMR below: -cycloheptanol -1-methylcyclohexanol -cyclohexanol -cyclopentanol -4-methylcyclohexanol 0 0. 8 0.7 UK-D 0.6 0.5 0.4 0.3 0.2 abundance 0.1 0 90.0 80.0 70.0 60.0 50.0 10.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 132.3 X: parts per Million : 13C 40.0 323 30.0 20.0 298 27.5
Assign each unknown to the correct carbon nmr spectra. *choices* cycloheptanol, 1-methylcyclohexanol, cyclohexanol, or cyclopentanol. Correctly assign all peaks Unknown A MW=68.1 100.0 0.0 BOLO Top X.parts per Minion 13C U B CARDON-jar UK-B MW= 82.1 N 190.0 1960 1960 1960 vso 160 1909 1960 wako nao meso 180 m 80.0 170.0 160.0 50.0 140.0 130 120.0 110.0 100.0 90.0 0.0 *********, pro 100 min 0.0 0.0 0.0 0 0.4 UK-C 77 ppm Coc, 0.3 en el www. WWWWWWWW W...
proposed the structure from C13 NMR with 9.2, 14.3,27.7,60.3,174.6 0 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 18.0 19.0 20.021 022 0230 (thousandths) 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110,0 100,0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 10. 0 0 100 300 174611
Characterization of product by H and C NMR spectrum analysis. Hi I just finished the Benzocaine synthesis for chem lab. I need help analyzing my NMR data for benzocaine. I've attached the proton and carbon NMR spectrum for benzocaine above. Please include as much infomation as possible and indicate if the results and reaction was a success. 1 andol 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0...
190.0 isoa 170.0 i600 tsoo 140.0 130.0 120.0 1100 100.0 90.0 80.0 700 600 50.0 40.0 30.0 20.0 10.0 X: parts per Million : 13C | Analyze the 13C NMR spectra. Draw the structure of your compound and assign ALL signals. Explain. based on your NMR analysis, which was your unknown starting material the produet prodcr clohepten