Question

Unknown BCARBON-2jar UK-B MW- 82.1 190.0 80.0 170.0 160.0 1S0.0 140.0 130. 120.0 110.o 100.0 90.0 70.0 60.0 50.0 40.0 30.0 20.0 10.0 27.2125

In this experiment you will synthesize an alkene reacting an alcohol with acid.You will start with one of four possible alcohols: cycloheptanol, cyclohexanol, 1-methylcyclohexanol, 4-methylcyclohexanol, and 1-methylcyclopentanol. You will use C13 NMR to identify the nature of the starting material and product.

So basically, what is the starting material and product based on the compound that is being shown in the NMR. Which alcohol is unknown B and which alkene corresponds with it? And how did you get this answer? Please show your work

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Answer 1

Basically synthesis of the alkene from the mixture of alcohol and acid, we must undergo dehydration of alkene mechanism.

As per above C13 NMR interpretation after analyzing it is identified that the starting material will be cyclohexane or its derivatives that undergoes with the help of strong acid to dehydrate and results in cyclohexene along with water. Because in the C13 it's clearly mentioned MW 82.1 and it's for cyclohexene.