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Assign each unknown to the correct carbon nmr spectra. *choices* cycloheptanol, 1-methylcyclohexanol, cyclohexanol, or...
Which unknown from the list represents the NMR below: -cycloheptanol -1-methylcyclohexanol -cyclohexanol -cyclopentanol -4-methylcyclohexanol 0 0....
Which unknown from the list represents the NMR below:
-cycloheptanol
-1-methylcyclohexanol
-cyclohexanol
-cyclopentanol
-4-methylcyclohexanol
0 0. 8 0.7 UK-D 0.6 0.5 0.4 0.3 0.2 abundance 0.1 0 90.0 80.0 70.0 60.0 50.0 10.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 132.3 X: parts per Million : 13C 40.0 323 30.0 20.0 298 27.5
For the 13C NMR, determine the unknown: Unknown Answers: -cycloheptanol -1-methylcyclohexanol - cyclohexanol - cylopentanol -4-methycyclohexanol...
For the 13C NMR, determine the unknown:
Unknown Answers:
-cycloheptanol
-1-methylcyclohexanol
- cyclohexanol
- cylopentanol
-4-methycyclohexanol
Unknown_B_CARBON-2.jar UK-B MW= 82.1 160.0 150.0 140.0 130.0 190.0 160.0 20.0 MOLO 170.0 110.0 100,0 70.0 90.0 0.0 0.0 0.0 0.0 0.0 20.0 100 177.2125 77,4207 77.0000 76.5793 25.1049 EILSU
How to interpret the C NMR of the complex 2-{[Dodecylsulfanyl) carbonothiolyl]sulfany) propanoic ...
How
to interpret the C NMR of the complex 2-{[Dodecylsulfanyl)
carbonothiolyl]sulfany) propanoic acid
C NMR SLT 0100 20.0 220.0 210.0 200.0 190.0 130.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 1000 90.0 800 70.0 600 500 400 300 20.0 10.0 XSparts per Mallion: Carbon13 C NMR 220.0 210.0 200.0 190.0 1800 1700 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 s0.0 700 60.0 500 40.0 30.0 20.0 10.0 0 -100 -20.0 xSparts per Million: Carbon13
C NMR SLT 0100 20.0...
Characterization of product by H and C NMR spectrum analysis. Hi I just finished the Benzocaine synthesis for chem lab. I need help analyzing my NMR data for benzocaine. I've attached the proton a...
Characterization of product by H and C NMR spectrum analysis. Hi
I just finished the Benzocaine synthesis for chem lab. I need help
analyzing my NMR data for benzocaine. I've attached the proton and
carbon NMR spectrum for benzocaine above. Please include as much
infomation as possible and indicate if the results and reaction was
a success.
1 andol 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0...
proposed the structure from C13 NMR with 9.2, 14.3,27.7,60.3,174.6 0 10 20 30 40 50 60...
proposed the structure from C13 NMR
with 9.2, 14.3,27.7,60.3,174.6
0 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 18.0 19.0 20.021 022 0230 (thousandths) 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110,0 100,0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 10. 0 0 100 300 174611
Is this unknown beta d-glucose based on these NMR's? PLEASE help me analyze the Carbon NMR...
Is
this unknown beta d-glucose based on these NMR's?
PLEASE help me analyze the Carbon NMR and the H NMR!
abundance 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 170.650 170.507 a170.135 169.878 969 691 77.299 77.041 76.793 68 352 68.085 62.028 61.742 20.794 20.660- 20.593 per Million : 130 abundance T 2.28 2.26 2.24 2.22 2.2 TTTTTTTTTTTTTTTTTTT 2.18 2.16 2.14 2.12 2.1 2.08 2.06 2.04 2.02 2.0 1.98 .96 1.94 1.92...
190.0 isoa 170.0 i600 tsoo 140.0 130.0 120.0 1100 100.0 90.0 80.0 700 600 50.0 40.0...
190.0 isoa 170.0 i600 tsoo 140.0 130.0 120.0 1100 100.0 90.0 80.0 700 600 50.0 40.0 30.0 20.0 10.0 X: parts per Million : 13C | Analyze the 13C NMR spectra. Draw the structure of your compound and assign ALL signals. Explain. based on your NMR analysis, which was your unknown starting material the produet prodcr clohepten
In this experiment you will synthesize an alkene reacting an alcohol with acid.You will start with one of four possible...
In this experiment you will synthesize an alkene reacting an
alcohol with acid.You will start with one of four possible
alcohols: cycloheptanol, cyclohexanol, 1-methylcyclohexanol,
4-methylcyclohexanol, and 1-methylcyclopentanol. You will use C13
NMR to identify the nature of the starting material and
product.
So basically, what is the starting material and product based on
the compound that is being shown in the NMR. Which alcohol is
unknown B and which alkene corresponds with it? And how did you get
this answer?...
D-Arabinose, can someone please analyze its Carbon and Proton NMR? abundance 170.0 160.0 150.0 140.0 130.0...
D-Arabinose, can someone please analyze its Carbon and Proton NMR?
abundance 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 20.0 70.650 2170.507 170.135 169.878 77.299 77041 76.793 969 by 68.352 68 OSS 62 028 61.742 20.794 20.660 1650 Paris per Million: 13C llion : 130 abundance ........20...3.0...40...50... ...6.0 . 7.0 8.0 2.132 2005 2070 - 2014 2.046 15.02
I need help with these spectrums to figure out the Dipeptide. can you explain each peak...
I need help with these spectrums to figure out the Dipeptide.
can you explain each peak and what the reasoning is.
80.0 170.0 160.0 150.0 140.0300 200 110.0 100.0 90.0 80.0 70.0 60.050.0 40.0 30.0 20.0 10. x: parts per Million: 13C
Which unknown from the list represents the NMR below:
-cycloheptanol
-1-methylcyclohexanol
-cyclohexanol
-cyclopentanol
-4-methylcyclohexanol
0 0. 8 0.7 UK-D 0.6 0.5 0.4 0.3 0.2 abundance 0.1 0 90.0 80.0 70.0 60.0 50.0 10.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 132.3 X: parts per Million : 13C 40.0 323 30.0 20.0 298 27.5
For the 13C NMR, determine the unknown:
Unknown Answers:
-cycloheptanol
-1-methylcyclohexanol
- cyclohexanol
- cylopentanol
-4-methycyclohexanol
Unknown_B_CARBON-2.jar UK-B MW= 82.1 160.0 150.0 140.0 130.0 190.0 160.0 20.0 MOLO 170.0 110.0 100,0 70.0 90.0 0.0 0.0 0.0 0.0 0.0 20.0 100 177.2125 77,4207 77.0000 76.5793 25.1049 EILSU
How
to interpret the C NMR of the complex 2-{[Dodecylsulfanyl)
carbonothiolyl]sulfany) propanoic acid
C NMR SLT 0100 20.0 220.0 210.0 200.0 190.0 130.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 1000 90.0 800 70.0 600 500 400 300 20.0 10.0 XSparts per Mallion: Carbon13 C NMR 220.0 210.0 200.0 190.0 1800 1700 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 s0.0 700 60.0 500 40.0 30.0 20.0 10.0 0 -100 -20.0 xSparts per Million: Carbon13
C NMR SLT 0100 20.0...
Characterization of product by H and C NMR spectrum analysis. Hi
I just finished the Benzocaine synthesis for chem lab. I need help
analyzing my NMR data for benzocaine. I've attached the proton and
carbon NMR spectrum for benzocaine above. Please include as much
infomation as possible and indicate if the results and reaction was
a success.
1 andol 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0...
proposed the structure from C13 NMR
with 9.2, 14.3,27.7,60.3,174.6
0 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 18.0 19.0 20.021 022 0230 (thousandths) 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110,0 100,0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 10. 0 0 100 300 174611
Is
this unknown beta d-glucose based on these NMR's?
PLEASE help me analyze the Carbon NMR and the H NMR!
abundance 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 170.650 170.507 a170.135 169.878 969 691 77.299 77.041 76.793 68 352 68.085 62.028 61.742 20.794 20.660- 20.593 per Million : 130 abundance T 2.28 2.26 2.24 2.22 2.2 TTTTTTTTTTTTTTTTTTT 2.18 2.16 2.14 2.12 2.1 2.08 2.06 2.04 2.02 2.0 1.98 .96 1.94 1.92...
190.0 isoa 170.0 i600 tsoo 140.0 130.0 120.0 1100 100.0 90.0 80.0 700 600 50.0 40.0 30.0 20.0 10.0 X: parts per Million : 13C | Analyze the 13C NMR spectra. Draw the structure of your compound and assign ALL signals. Explain. based on your NMR analysis, which was your unknown starting material the produet prodcr clohepten
In this experiment you will synthesize an alkene reacting an
alcohol with acid.You will start with one of four possible
alcohols: cycloheptanol, cyclohexanol, 1-methylcyclohexanol,
4-methylcyclohexanol, and 1-methylcyclopentanol. You will use C13
NMR to identify the nature of the starting material and
product.
So basically, what is the starting material and product based on
the compound that is being shown in the NMR. Which alcohol is
unknown B and which alkene corresponds with it? And how did you get
this answer?...
D-Arabinose, can someone please analyze its Carbon and Proton NMR?
abundance 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 20.0 70.650 2170.507 170.135 169.878 77.299 77041 76.793 969 by 68.352 68 OSS 62 028 61.742 20.794 20.660 1650 Paris per Million: 13C llion : 130 abundance ........20...3.0...40...50... ...6.0 . 7.0 8.0 2.132 2005 2070 - 2014 2.046 15.02
I need help with these spectrums to figure out the Dipeptide.
can you explain each peak and what the reasoning is.
80.0 170.0 160.0 150.0 140.0300 200 110.0 100.0 90.0 80.0 70.0 60.050.0 40.0 30.0 20.0 10. x: parts per Million: 13C
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