Which unknown from the list represents the NMR below:
-cycloheptanol
-1-methylcyclohexanol
-cyclohexanol
-cyclopentanol
-4-methylcyclohexanol
Homework Answers
![cs NMR peak at 132.3 ppm indicates presence of spe carben (Alkene] in your spe carbon. choice no compound have So none of the](http://img.homeworklib.com/questions/a9a1cdb0-72dd-11ea-b4ef-f9e654a58e40.png?x-oss-process=image/resize,w_560)
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Which unknown from the list represents the NMR below:
-cycloheptanol
-1-methylcyclohexanol
-cyclohexanol
-cyclopentanol
-4-methylcyclohexanol
0 0....
Assign each unknown to the correct carbon nmr spectra. *choices* cycloheptanol, 1-methylcyclohexanol, cyclohexanol, or...
Assign each unknown to the correct carbon nmr spectra. *choices*
cycloheptanol, 1-methylcyclohexanol, cyclohexanol, or
cyclopentanol. Correctly assign all peaks
Unknown A MW=68.1 100.0 0.0 BOLO Top X.parts per Minion 13C U B CARDON-jar UK-B MW= 82.1 N 190.0 1960 1960 1960 vso 160 1909 1960 wako nao meso 180 m 80.0 170.0 160.0 50.0 140.0 130 120.0 110.0 100.0 90.0 0.0 *********, pro 100 min 0.0 0.0 0.0 0 0.4 UK-C 77 ppm Coc, 0.3 en el www. WWWWWWWW W...
For the 13C NMR, determine the unknown: Unknown Answers: -cycloheptanol -1-methylcyclohexanol - cyclohexanol - cylopentanol -4-methycyclohexanol...
For the 13C NMR, determine the unknown:
Unknown Answers:
-cycloheptanol
-1-methylcyclohexanol
- cyclohexanol
- cylopentanol
-4-methycyclohexanol
Unknown_B_CARBON-2.jar UK-B MW= 82.1 160.0 150.0 140.0 130.0 190.0 160.0 20.0 MOLO 170.0 110.0 100,0 70.0 90.0 0.0 0.0 0.0 0.0 0.0 20.0 100 177.2125 77,4207 77.0000 76.5793 25.1049 EILSU
How to interpret the C NMR of the complex 2-{[Dodecylsulfanyl) carbonothiolyl]sulfany) propanoic ...
How
to interpret the C NMR of the complex 2-{[Dodecylsulfanyl)
carbonothiolyl]sulfany) propanoic acid
C NMR SLT 0100 20.0 220.0 210.0 200.0 190.0 130.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 1000 90.0 800 70.0 600 500 400 300 20.0 10.0 XSparts per Mallion: Carbon13 C NMR 220.0 210.0 200.0 190.0 1800 1700 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 s0.0 700 60.0 500 40.0 30.0 20.0 10.0 0 -100 -20.0 xSparts per Million: Carbon13
C NMR SLT 0100 20.0...
Characterization of product by H and C NMR spectrum analysis. Hi I just finished the Benzocaine synthesis for chem lab. I need help analyzing my NMR data for benzocaine. I've attached the proton a...
Characterization of product by H and C NMR spectrum analysis. Hi
I just finished the Benzocaine synthesis for chem lab. I need help
analyzing my NMR data for benzocaine. I've attached the proton and
carbon NMR spectrum for benzocaine above. Please include as much
infomation as possible and indicate if the results and reaction was
a success.
1 andol 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0...
proposed the structure from C13 NMR with 9.2, 14.3,27.7,60.3,174.6 0 10 20 30 40 50 60...
proposed the structure from C13 NMR
with 9.2, 14.3,27.7,60.3,174.6
0 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 18.0 19.0 20.021 022 0230 (thousandths) 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110,0 100,0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 10. 0 0 100 300 174611
D-Arabinose, can someone please analyze its Carbon and Proton NMR? abundance 170.0 160.0 150.0 140.0 130.0...
D-Arabinose, can someone please analyze its Carbon and Proton NMR?
abundance 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 20.0 70.650 2170.507 170.135 169.878 77.299 77041 76.793 969 by 68.352 68 OSS 62 028 61.742 20.794 20.660 1650 Paris per Million: 13C llion : 130 abundance ........20...3.0...40...50... ...6.0 . 7.0 8.0 2.132 2005 2070 - 2014 2.046 15.02
In this experiment you will synthesize an alkene reacting an alcohol with acid.You will start with one of four possible...
In this experiment you will synthesize an alkene reacting an
alcohol with acid.You will start with one of four possible
alcohols: cycloheptanol, cyclohexanol, 1-methylcyclohexanol,
4-methylcyclohexanol, and 1-methylcyclopentanol. You will use C13
NMR to identify the nature of the starting material and
product.
So basically, what is the starting material and product based on
the compound that is being shown in the NMR. Which alcohol is
unknown B and which alkene corresponds with it? And how did you get
this answer?...
Is this unknown beta d-glucose based on these NMR's? PLEASE help me analyze the Carbon NMR...
Is
this unknown beta d-glucose based on these NMR's?
PLEASE help me analyze the Carbon NMR and the H NMR!
abundance 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 170.650 170.507 a170.135 169.878 969 691 77.299 77.041 76.793 68 352 68.085 62.028 61.742 20.794 20.660- 20.593 per Million : 130 abundance T 2.28 2.26 2.24 2.22 2.2 TTTTTTTTTTTTTTTTTTT 2.18 2.16 2.14 2.12 2.1 2.08 2.06 2.04 2.02 2.0 1.98 .96 1.94 1.92...
For the 13C NMR, determine the unknown: Unknown Answers: -cycloheptanol -1-methylcyclohexanol - cyclohexanol - cylopentanol -4-methycyclohexanol...
For the 13C NMR, determine the unknown:
Unknown Answers:
-cycloheptanol
-1-methylcyclohexanol
- cyclohexanol
- cylopentanol
-4-methycyclohexanol
parts per Million : 13C MW=68.1 Unknown A 69.7063 894774 32.2779 201918 31.3717 30.9234 20.5362 19.859) 19.6301 19.1818
Below are pictures of my HNMR and CNMR for salenH2. I have already assigned some of...
Below are pictures of my HNMR and CNMR for salenH2. I have already
assigned some of the protons and carbons myself, but I am having
trouble with the rest. As far as I know, there are 8 unique carbons
and 7 unique hydrogens. The carbons are numbered and the hydrogens
are lettered. I have included a labeled picture of the compound on
each page.
CNMR overall:
CNMR zoomed:
HNMR overall:
HNMR zoomed:
Thanks!
(thousandths) 0 2.0 4.0 6.0 8.0 10.0...
Assign each unknown to the correct carbon nmr spectra. *choices*
cycloheptanol, 1-methylcyclohexanol, cyclohexanol, or
cyclopentanol. Correctly assign all peaks
Unknown A MW=68.1 100.0 0.0 BOLO Top X.parts per Minion 13C U B CARDON-jar UK-B MW= 82.1 N 190.0 1960 1960 1960 vso 160 1909 1960 wako nao meso 180 m 80.0 170.0 160.0 50.0 140.0 130 120.0 110.0 100.0 90.0 0.0 *********, pro 100 min 0.0 0.0 0.0 0 0.4 UK-C 77 ppm Coc, 0.3 en el www. WWWWWWWW W...
For the 13C NMR, determine the unknown:
Unknown Answers:
-cycloheptanol
-1-methylcyclohexanol
- cyclohexanol
- cylopentanol
-4-methycyclohexanol
Unknown_B_CARBON-2.jar UK-B MW= 82.1 160.0 150.0 140.0 130.0 190.0 160.0 20.0 MOLO 170.0 110.0 100,0 70.0 90.0 0.0 0.0 0.0 0.0 0.0 20.0 100 177.2125 77,4207 77.0000 76.5793 25.1049 EILSU
How
to interpret the C NMR of the complex 2-{[Dodecylsulfanyl)
carbonothiolyl]sulfany) propanoic acid
C NMR SLT 0100 20.0 220.0 210.0 200.0 190.0 130.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 1000 90.0 800 70.0 600 500 400 300 20.0 10.0 XSparts per Mallion: Carbon13 C NMR 220.0 210.0 200.0 190.0 1800 1700 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 s0.0 700 60.0 500 40.0 30.0 20.0 10.0 0 -100 -20.0 xSparts per Million: Carbon13
C NMR SLT 0100 20.0...
Characterization of product by H and C NMR spectrum analysis. Hi
I just finished the Benzocaine synthesis for chem lab. I need help
analyzing my NMR data for benzocaine. I've attached the proton and
carbon NMR spectrum for benzocaine above. Please include as much
infomation as possible and indicate if the results and reaction was
a success.
1 andol 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0...
proposed the structure from C13 NMR
with 9.2, 14.3,27.7,60.3,174.6
0 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 18.0 19.0 20.021 022 0230 (thousandths) 220.0 210.0 200.0 190.0 180.0 170.0 160.0 150.0 140.0 130.0 120.0 110,0 100,0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 10. 0 0 100 300 174611
D-Arabinose, can someone please analyze its Carbon and Proton NMR?
abundance 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 20.0 70.650 2170.507 170.135 169.878 77.299 77041 76.793 969 by 68.352 68 OSS 62 028 61.742 20.794 20.660 1650 Paris per Million: 13C llion : 130 abundance ........20...3.0...40...50... ...6.0 . 7.0 8.0 2.132 2005 2070 - 2014 2.046 15.02
In this experiment you will synthesize an alkene reacting an
alcohol with acid.You will start with one of four possible
alcohols: cycloheptanol, cyclohexanol, 1-methylcyclohexanol,
4-methylcyclohexanol, and 1-methylcyclopentanol. You will use C13
NMR to identify the nature of the starting material and
product.
So basically, what is the starting material and product based on
the compound that is being shown in the NMR. Which alcohol is
unknown B and which alkene corresponds with it? And how did you get
this answer?...
Is
this unknown beta d-glucose based on these NMR's?
PLEASE help me analyze the Carbon NMR and the H NMR!
abundance 170.0 160.0 150.0 140.0 130.0 120.0 110.0 100.0 90.0 80.0 70.0 60.0 50.0 40.0 30.0 20.0 170.650 170.507 a170.135 169.878 969 691 77.299 77.041 76.793 68 352 68.085 62.028 61.742 20.794 20.660- 20.593 per Million : 130 abundance T 2.28 2.26 2.24 2.22 2.2 TTTTTTTTTTTTTTTTTTT 2.18 2.16 2.14 2.12 2.1 2.08 2.06 2.04 2.02 2.0 1.98 .96 1.94 1.92...
For the 13C NMR, determine the unknown:
Unknown Answers:
-cycloheptanol
-1-methylcyclohexanol
- cyclohexanol
- cylopentanol
-4-methycyclohexanol
parts per Million : 13C MW=68.1 Unknown A 69.7063 894774 32.2779 201918 31.3717 30.9234 20.5362 19.859) 19.6301 19.1818
Below are pictures of my HNMR and CNMR for salenH2. I have already
assigned some of the protons and carbons myself, but I am having
trouble with the rest. As far as I know, there are 8 unique carbons
and 7 unique hydrogens. The carbons are numbered and the hydrogens
are lettered. I have included a labeled picture of the compound on
each page.
CNMR overall:
CNMR zoomed:
HNMR overall:
HNMR zoomed:
Thanks!
(thousandths) 0 2.0 4.0 6.0 8.0 10.0...
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