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![Amt of Masoy = 0.375g no of mole of Mnsoy = 0.375 151 [ Mn5o4] = 0. 375 151 M 0.460 = 5140 x 10-3 m. Mnsou X Mnsou = MEDTA X](http://img.homeworklib.com/questions/d2527450-1e71-11ea-a85a-0fb799151422.png?x-oss-process=image/resize,w_560)
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A 48.30 mL aliquot from a 0.460 L solution that contains 0.375 g of MnSO, (MW = 151.00 g/mol) required 39.9 mL of an ED...
A 48.50 mL aliquot from a 0.475 L solution that contains 0.495 g of MnSO 4...
A 48.50 mL aliquot from a 0.475 L solution that contains 0.495 g of MnSO 4 ( MW = 151.00 g/mol) required 37.2 mL of an EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCO 3 ( MW = 100.09 g/mol) will react with 1.00 mL of the EDTA solution?
A 47.30 mL aliquot from a 0.485 L solution that contains 0.465 g of MnSO4 (MW=151.00...
A 47.30 mL aliquot from a 0.485 L solution that contains 0.465 g
of MnSO4 (MW=151.00 g/mol) required 39.4 mL of an EDTA solution to
reach the end point in a titration. What mass, in milligrams, of
CaCO3 ( MW=100.09 g/mol) will react with 1.78 mL of the EDTA
solution?
A 47.30 mL aliquot from a 0.485 L solution that contains 0.465 g of MnSO4 (MW = 151.00 g/mol) required 39.4 mL of an EDTA solution to reach the end...
A 48.80 mL aliquot from a 0.505 L solution that contains 0.525 g of MnSOg (MW...
A 48.80 mL aliquot from a 0.505 L solution that contains 0.525 g of MnSOg (MW EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCo3 (MW 100.09 g/mol) will react 151.00 g/mol) required 40.8 mL of an with 1.80 mL of the EDTA solution? mass mg
A 50.00 mL aliquot from a 0.490 L solution that contains 0.470 g of MnSO4 (...
A 50.00 mL aliquot from a 0.490 L solution that contains 0.470 g of MnSO4 ( MW=151.00 g/mol) required 38.0 mL of an EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCO3 ( MW=100.09 g/mol) will react with 1.00 mL of the EDTA solution? mass: mg
explanation A 47.90 mL aliquot from a 0.510 L solution that contains 0.485 g of MnSO4...
explanation
A 47.90 mL aliquot from a 0.510 L solution that contains 0.485 g of MnSO4 (Fw 151.00 g/mol) required 35.0 mL of an EDTA solution to reach the end point in a titration. What mass (in milligrams) of CaCO3 (FW 100.09 g/mol) will react with 1.63 m of the EDTA solution? Number Caco, mass 1406.18 mg
Please help! Will rate. Cd" forms two complexes with acetate, with the given overall formation constants....
Please help! Will rate.
Cd" forms two complexes with acetate, with the given overall formation constants. 1. Cd2+ (aq) + CH, COŽ (aq) =C(CH.CO2)+(aq) 2. Cd²+ (aq) + 2CH,CO2 (aq) = CaCH,CO2),(aq) R = B = 85 B2 = 1400 Find the stepwise formation constant, K2, for the reaction 3. Cd(CH, CO)* (aq) +CHCO, (aq) = Ca(CH, CO ) (aq) Kg =? You prepare 1.00L of solution containing 1.00 x 10-mol Ca(CIO), and 0.260 mol CH, CO, Na. Calculate the...
Name Section Experiment 28 Advance Study Assignment: Determination of the Hardness of Water 1. A 0.3946...
Name Section Experiment 28 Advance Study Assignment: Determination of the Hardness of Water 1. A 0.3946 g sample of Caco, is dissolved in 12 M HCl and the resulting solution is diluted to 250.0 mL in a volumetric flask. a. How many moles of Caco, are used (formula mass = 100.1)? moles b. What is the molarity of the Ca2+ in the 250 mL of solution? c. How many moles of Caare in a 25.00-mL aliquot of the solution in...
A solution contains 1.577 mg of CoSO4 (155.0 g/mol) per milliliter. Calculate a. the volume of...
A solution contains 1.577 mg of CoSO4 (155.0 g/mol) per milliliter. Calculate a. the volume of 0.007840 M EDTA needed to titrate a 25.00-mL aliquot of this solution. Volume = mL b. the volume of 0.006901 M Zn2+ needed to titrate the excess reagent after addition of 50.00 mL of 0.007840 M EDTA to a 25.00-mL aliquot of this solution. Volume = mL c. the volume of 0.007840 M EDTA needed to titrate the Zn2+ displaced by Co2+ following addition...
Chloride (35.45 g/mol) in a brine solution is determined by the Volhard method. A 14.17-ml aliquot...
Chloride (35.45 g/mol) in a brine solution is determined by the Volhard method. A 14.17-ml aliquot of the solution is treated with 14.68 mL of standard 0.1009 M AgNO3 solution. The excess silver is titrated with standard 0.103 M KSCN solution, requiring 2.9 ml. to reach the red Fe(CN)2end point. Calculate the % (wv) Cr content of the solution (1) Agar Agai (2) AgSCN + AgSCN Note: Carry out the complete solution then round off the answer to 3 significant...
A) A chemist prepares a solution by adding 304 mg of Co(NO3)2 (MW = 182.94 g/mol)...
A) A chemist prepares a solution by adding 304 mg of Co(NO3)2 (MW = 182.94 g/mol) to a volumetric flask, and then adding water until the total volume of the contents of the flask reaches the calibration line that indicates 100 mL. Determine the molarity of the prepared solution. B) Determine the mass of chloride (MW = 35.45 g/mol) in grams present in 100mL of a 0.289 M solution of aqueous FeCl3 (iron(III) chloride). C) A beaker contains 250 mL...
A 47.30 mL aliquot from a 0.485 L solution that contains 0.465 g
of MnSO4 (MW=151.00 g/mol) required 39.4 mL of an EDTA solution to
reach the end point in a titration. What mass, in milligrams, of
CaCO3 ( MW=100.09 g/mol) will react with 1.78 mL of the EDTA
solution?
A 47.30 mL aliquot from a 0.485 L solution that contains 0.465 g of MnSO4 (MW = 151.00 g/mol) required 39.4 mL of an EDTA solution to reach the end...
A 48.80 mL aliquot from a 0.505 L solution that contains 0.525 g of MnSOg (MW EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCo3 (MW 100.09 g/mol) will react 151.00 g/mol) required 40.8 mL of an with 1.80 mL of the EDTA solution? mass mg
explanation
A 47.90 mL aliquot from a 0.510 L solution that contains 0.485 g of MnSO4 (Fw 151.00 g/mol) required 35.0 mL of an EDTA solution to reach the end point in a titration. What mass (in milligrams) of CaCO3 (FW 100.09 g/mol) will react with 1.63 m of the EDTA solution? Number Caco, mass 1406.18 mg
Please help! Will rate.
Cd" forms two complexes with acetate, with the given overall formation constants. 1. Cd2+ (aq) + CH, COŽ (aq) =C(CH.CO2)+(aq) 2. Cd²+ (aq) + 2CH,CO2 (aq) = CaCH,CO2),(aq) R = B = 85 B2 = 1400 Find the stepwise formation constant, K2, for the reaction 3. Cd(CH, CO)* (aq) +CHCO, (aq) = Ca(CH, CO ) (aq) Kg =? You prepare 1.00L of solution containing 1.00 x 10-mol Ca(CIO), and 0.260 mol CH, CO, Na. Calculate the...
Name Section Experiment 28 Advance Study Assignment: Determination of the Hardness of Water 1. A 0.3946 g sample of Caco, is dissolved in 12 M HCl and the resulting solution is diluted to 250.0 mL in a volumetric flask. a. How many moles of Caco, are used (formula mass = 100.1)? moles b. What is the molarity of the Ca2+ in the 250 mL of solution? c. How many moles of Caare in a 25.00-mL aliquot of the solution in...
A solution contains 1.577 mg of CoSO4 (155.0 g/mol) per milliliter. Calculate a. the volume of 0.007840 M EDTA needed to titrate a 25.00-mL aliquot of this solution. Volume = mL b. the volume of 0.006901 M Zn2+ needed to titrate the excess reagent after addition of 50.00 mL of 0.007840 M EDTA to a 25.00-mL aliquot of this solution. Volume = mL c. the volume of 0.007840 M EDTA needed to titrate the Zn2+ displaced by Co2+ following addition...
Chloride (35.45 g/mol) in a brine solution is determined by the Volhard method. A 14.17-ml aliquot of the solution is treated with 14.68 mL of standard 0.1009 M AgNO3 solution. The excess silver is titrated with standard 0.103 M KSCN solution, requiring 2.9 ml. to reach the red Fe(CN)2end point. Calculate the % (wv) Cr content of the solution (1) Agar Agai (2) AgSCN + AgSCN Note: Carry out the complete solution then round off the answer to 3 significant...
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