Question
Can you please explain to me why it is (16-r^2) when it is being integrated?
of the solid that is inside Fin d the volume ty and under the plane Z 16.
2 T =/(16-2)r dr de r 0 2T 4 (16r r) dr d0 r=0 277 8p2 dr de 4 =O 27T (64) dr d0 - 128T.
of the solid that is inside Fin d the volume ty and under the plane Z 16.
2 T =/(16-2)r dr de r 0 2T 4 (16r r) dr d0 r=0 277 8p2 dr de 4 =O 27T (64) dr d0 - 128T.
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Answer #1

2 2 Z=メ+y see i Panaboloid Region ds integrohm using Polar Coordinales 9ニY in9 ak ヤラメラ0 2 z 16 人ニ 2TT y 2. TT 4 2- C 2TT (6-r

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