Question

(2n 1)2nn! 2 V2T n=0 Since this is an alternating series (because the parity on the power on x means that will always have th    #1 please and the answer should be in the form of a piecewise function

0 0
Add a comment Improve this question Transcribed image text
Answer #1

1.

The probability density function must be positive between -1 and 1.

Also, since it represents picking a number at random, its value must be the same for all numbers

between -1 and 1, then the function is constant in the interval [-1,1]

Therefore the function is of the form

if -1 f(x) kif 1 1 if 1 0

where k is a constant.

Now, recall that the integral of a PDF over all reals must be equal to 1.

Hence

roo kdr 1 f(x)dx

Then

(1)

k(1 (1)) 1

2

Thus, the PDF is

if r 1 if 1 1 if r 0 f (x) 2 0 1

Add a comment
Know the answer?
Add Answer to:
   #1 please and the answer should be in the form of a piecewise function (2n 1)2nn! 2 V2T n=0 Since this is an alterna...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT