Question

Calculate the molarity of each of the following: a. 2.00 mol of glucose in 4.00 L of a glucose solution b. 4.00 g of KOH in 2.00 L of a KOH solution c. 5.85 g of NaCl in 400. mL of a NaCl solution

Answer 1

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Molanity - volume of solution (4) - Molanity = no. of moles of solute (mol mo); no. of moles= mass (9) molar mass i Molarity mass of solute (9) (g/mol) Molar Mass of solute (almol volume of solution (2) @ M=?? n = 2.0 mot; v4.0L - M = W = 2.0m - 0.5 mol/L - (0.5M) 16 mass = 4.009; V=2.0L molar mass of KOH= 56.1 g/mol M= 4:09 mpho = 0.035 mol/l = 0.03514) © mars = 5.859 ; molar mass of Nace = 58.5g/mol, V = 400.0ml = 0.40L M= 5.85g 1- 58.5 g/mol 0.4L = 0.25 mol/L = 0.25M @ M=1.50M = 1.50 mohl ; V=2.0L molar mass of Naof I 40 g/mol mass = molarity) (molar mass) (volume) = (1.someth) (40. g/mol) (2-02) = (120g of NooH 6 M = 0.20M = 0.20 mol/L ; V=4.00L; molar mass of kee = 74.55 g/mol mass = (0,20 mol/L) (4.0L) (74.55 g/mol) = (59.64g of kell 2 @ M=6.0M = 6.0 mol/L; V= 25.0mL = 0.025 L (100mL. IL)! molar mass of HCl = 36.5 g/mol mass = (6.0 mol/L) (36.5 g mol) (0.025L) = (3.475 g) of He