Question

6.16 Classify each of the following solutes as an electrolyte or a nonelectrolyte

a. NaNO₃

b. C₆H₁₂O₆

c. FeCl₃

6.26a Calculate the composition of 20.0 g acetic acid dissolved in 2.50 L in mass/volume%

6.28b Calculate the %m/m composition of 50.0 g KCl in 5.00 x 10² mL solution (d=1.14g/mL)

6.30a How many g of solute are needed to prepare 2.50x102 g of 5.00% (m/m) NH₄Cl?

6.34 How many mL of 4.0 mass/volume % Mg(NO₃)₂ solution would contain 1.2 g of magnesium nitrate?

6.42 Calculate the molarity of 2.75 L of solution containing 1.35x10^-2 mol HCl

6,44b Calculate the number of g of solute to make 2.50x10² mL of 0.200 M KOH.

6.46 Calculate the volume of a 1.00x10^-2M KOH solution containing 3.00x10^-1 mol of solute.

6.48 A 50.0 mL sample of a 0.250 M sucrose solution was diluted to 5.00x10² mL What is the molar concentration of the resulting solution?

6.50 A 6.00 mL portion of an 8.00 M stock solution is to be diluted to 0.400 M. What will be the final volume after dilution?

6.74 + 6.76 Determine whether there will be a net flow of water in one direction and, if so, which direction?

A is 0.10 M glucose and B is 0.10 M KCl

A is 0.10 M NaCl and B is 0.20 M glucose

6.88 Name the two most important cations in biological fluids.

6.102 Calculate the number of eq/L of SO₄^2- in a solution that is 2.5x10^-3 M in SO₄^2-

1. Which of the following aqueous solutions has the highest boiling point?

                A)        0.2 m KCl                                                             D)        A and B.

                B)         0.2 m Na₂SO₄                                                     E)         B and C.

                C)         0.2 m Ca(NO₃)₂

2. Consider the following aqueous solutions. Which one has the highest vapor pressure? Which one has the highest boiling point? Which one has the highest freezing point?

A. 0.2 M NaCl      B. 0.3 M C₆H₁₂O₆

Answer 1

6 -16 electrolyte are thase soute which conduct do nót electricity while non Conduct electricit elect rolyte electroyte Non electrolyte s NaNOg, feci3 CGHi2% 6.26 a mass ofsolute we know X 10 0 % mass Volume of solution Cinmi) Volume 2.5L = 2500ml 20 gm % mass %3D XIDD rolume %8.0= 2500mI 6.28b deasity Given d = 1.14gm/ml - mass we know Volume V = S.00x1omL 1-14 gm x 5.00x1 Vxd = mass = mass = 570gm of solufon we know % mass = mass of solute mass of solution X 100 mass 50 gm 8-77 % -XI00 570gm G.30a we know mass of solute mass of solufion % mass mass Given *(m/m) solution a 250X10 gm mass of m/m)k mass of solution mass of salute = 2.50x10 gm = (12.5 gm lo0 Scanned with CamScanner

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