Question

please help me find thr Average molaritt of NAOH and the percision RAD as well

please show work

Date: Instructor LABORATORY REPORT FORM molar mass of KHC H,O4 Sample # g/mole 22,391 22.4345 232 AAW 21.137 264 1 4 Masses of KHC,H,O4 Samples Mass of bottle + sample 2223 22 23 21.7361 3 0.7420370 0S 0.S01 0.111 036 Mass of bottle + remaining material Mass of sample 7-50 17.90 135 Buret Readings mL Final reading O,00 0.00 0,50 mL 4,8 Initial reading 5064ml 150l 114 6.451m Volume NAOH added mo Calculation of Molar Concentration Average molarity NaOH M Precision as RAD ppt moles Molarity of NaOH= L NaOH used In order to determine if there are any errors in the titrations, the precision of the analysis is calculated as Relative Average Deviation, i.e. RAD, from the mean. The process involves steps outlined below. It can be also reviewed by watching a video: http://voutu.be/6f13Wq6yxcY 2. average deviation, d x- x where: X each individual molarity the average molarity nthe number of trials = X Precision as RAD: (in parts per thousand, i.e. ppt) average deviation x 1000 average molarity The value should be 10 ppt, or less. If it is larger, additional titrations should be performed. Boret Beading 2. 17.96 Emgl eading SS.49 Tatial herding 4.9 Volene of NA6H 54.6ml 7S0 6,00 7,35 6.S049 17.10ml 6.84 51 m O.6.0 7.Sdml Calo lation of males WaoH Valotme Na OH Molay Concentade Malarity NACH Average Malarnty NAOH Pab Perasion Mass of hHeg Hy Oy 2 26499 Mass af botHersarple 22 8345 222381 21,7367 21.736 7 207499 mass of botHe eminiog matl 32238 20.3876 0.366l9 of S4m ple O.45 0.504 0.9919 Mass Calcalation Moles of

Answer 1

Molecular formula of acid: KHCsH4O4 Base used for titration is: NaOH Molar mass of acid from the given molecular formula (39)+(1)+(8*12)+(4*1)+(4"16) wwww.wM 204 g/mol Mass of KHC8H404 Moles of KHCsH4O4 0.45 0.5014 0.9919 0.36689 0.002205 0.0024578 0.00486225 0.00179848 For acid-base neutralization reaction if both acid and base are monobasic and monoacidic respectively then Moles of acid = moles of base or Moles of acid Molarity of base x Volume of base (in Litre) Therefore, Volume of NaOH Molarity of NaOH 6.8451 50.64 7.50 17.90 0.2716345 0.04356008 0.327712142 0.2627398 Now x 0.22641163 d 0.0914257755 Precision as RAD = 403.80