Question

Example On September 19, 1991, a German couple hiking in the Italian Alps discovered a body trapped in the ice. Subsequent investigation revealed the remarkably well- preserved body to be that of a Stone Age man. When the carbon-14 (T1/2=5730 y) dating method was applied to the remains of the Iceman and some of the materials he had carried with him, it was found that the carbon-14 activity was about 0.121 Bq per gram of carbon. Using this information, date the remains of the Iceman. 0.231 Carbon-14 activity (5) 0.121 0.116 R=0,121 Bq Tyz = 57304 to en Ro=0,23 1 Bq s 0 0.2 0.4 1.2 1.4 0.6 0.8 1.0 Half-lives (T12-5730 y)

I understand how to do this problem. My problem is that I do not understand where the Ro variable is coming from. Can someone please explain how Ro=0.231 Bq was found? I would really appreciate it.

Answer 1

Ro is Intial at that activity time is t o which guien in graph is clearly at 1. so tao acturity = 0.231 Bq Ro= (Initial actunity ) 30-231 B2