Question

R. In a particular city, 82% of the residents have a desktop computer, 47% have a desktop computer and a laptop computer, and 3% have neither a desktop laptop computer. nor a (63) The probability that a randomly selected home has (b) 0.62 laptop is (d) 0.97 (c) 0.79 (a) 0.35 (64) Given that a randomly selected home has a desktop computer, the probability that this home does not have a laptop computer is (c) 0.51 (d) 0.55 (b) 0.43 (a) 0.28

Answer 1

63)

P(D) = 82% and P (L) = x

P (neither D nor L) = 3% and P (D and L) = 47%

P (D) + P (L) - P (D and L) + P (neither D nor L) = 100%

82% + x - 47% + 3% = 100%

x = 62% (option B is correct)

64)

P (L')/P(D) = (82% - 47%)/82% = 43% (option B is correct)