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its already all the question, there is no more I can add.

1. On Tuesday (June 4th), we have considered В - Вk E Ej and showed that the trajectory of the point charge is given by E -t (1 cos (1) у() %3D - sin cwt subject to initial conditions of (x(0),y(0)) = (0,0) and (v(0), v,(0)) = (E/B, ). Choose a pro- gram or an online service website at your own choice to visualize Eq. (1), considering: (5 points) (5 points) (а) Е/В — 0 (b) Е/В < (5 points) (с) Е/В (d) E/B (5 points) y V=1and considerE [0,6. Finally, google "cycloid" and (5 points) For simplicity, you may assume o = compare your results for (a)-(d). Which one corresponds to the cycloid?

Answer 1

E/M=0

E/M<1

3 2 10 12 14 16 18 8 2

E/M=1 , This is the Cycloid.

3 2 10 12 14 16 18 1 2 st

E/M>1

18 16 12 14 10 -7 3 -00 -N

18 16 12 14 10 -7 3