4.
a) Triphenylmethyl chloride will form tertiary carbocation first which is rate determining step and then 2-propanol will attack on carbocation so will get our desired product. So this is SN1 reaction.
b) 4-methyl-1-butanol was converted to 4-methylbutyl chloride using POCl3 in step1. Then this alkyl halide will trat with NaCN to get desired product, step2 is SN2 reaction.
5.
a) This reaction is known as Finkelstein reaction, in this reaction iodine act as nucleophile and attack on back side of bromine to get inversion of of configuration of product and sodium bromide as a byproduct.
please provide a detail explanation how to solve for thumbs up r e c ast Periode table of Com CCHE 232 Mov Comparin...