Question
Can someoneplease help me with #3 - to find Etheo and Theta?

I think the correct andwer is theta = 79.94
but i keep getting something else.

Analysis Calculate Ethe and Oneo from the forces given in the problem (F, etc.). See the introduction for outline of the proc
ntroduction This lab experimentally verifies the technique of vector addition by components and introduces the idea of forces
Fsta5 cos los -52.83 1as siNGs=113.28 Far 185 cos los 73.(8 ののし 7494 952-83 +78.19 131.91 sy oy 3.2867.4l0 Ry 2 f0.94 Ey-Rf (
Analysis Calculate Ethe and Oneo from the forces given in the problem (F, etc.). See the introduction for outline of the procedure. an Calculate the differences between experimental and theoretical values. Standards: Theoretical and experimental force magnitudes should agree to within 5 grams. Theoretical and experimental force directions should agree to within 2° Problems for Experiment Practice Problem You need not record data for the practice problem. It's there to give you the chance to practice the experimental procedure and calculations. F=165 g@300 F 235 g@ 150° irdes dgsosy Answer: Exheo = 124 g@ 12° Problems 1 F, 125 g@10° F=95 g@ 90° lgine ol 2| F, 90 g@21 2 F.=162 g@270° F&=185 g@265° o od bulari oT 3 F,=125 g @65°
ntroduction This lab experimentally verifies the technique of vector addition by components and introduces the idea of forces in equilibrium. Static equilibrium is a state of rest, and it requires that the vector sum of all forces acting on a body be zero. In this lab, when three or more forces of the right magnitude and direction are ring (by means of masses suspended on strings running over pulleys) their vector sum is zero, and the ring is in static equilibrium at the center of the force table. applied to a metal For example, suppose you first apply forces F, and F, to the ring (you can imagine it at the coordi nate origin): F. F. here shown graphically: The vector sum of the applied forces (the resultant) is R = F, + F F F R so the ring isn't in static equilibrium yet. To balance the applied an additional force E, the equilibrant. Mathematically, the vecto The resultant R isn't zero, and reach equilibrium, apply is Fi+F+E=0. Graphically, it looks like this: F F. E that the equilibrant is equal and opposite the resultant: E = -R You can see
Fsta5 cos los -52.83 1as siNGs=113.28 Far 185 cos los 73.(8 ののし 7494 952-83 +78.19 131.91 sy oy 3.2867.4l0 Ry 2 f0.94 Ey-Rf (31.0 Ey--Ry - To.94 17143,680t t 76927.28 30
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Answer #1

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