When 25.0 mL of a
4.80×10-4M potassium
sulfate solution is combined with 15.0 mL
of a 4.27×10-4M calcium
acetate solution does a precipitate
form? (yes or no)
For these conditions the Reaction Quotient, Q, is equal to ?
The molar solubility of calcium sulfite in a 0.158 M potassium sulfite solution is ? M.
Solid cobalt(II) acetate is slowly added to 50.0 mL of a 0.0327 M potassium carbonate solution. The concentration of cobalt(II) ion required to just initiate precipitation is ? M
The volume of water needed to dissolve 0.0721 grams of silver sulfate is ? L.(Assume no volume change upon addition of the solid.)
.
Q1. When 25.0 mL of a 4.80×10-4 M potassium sulfate solution is combined with 15.0 mL of a 4.27×10-4 M calcium acetate solution does a precipitate form? : No
For these conditions the Reaction Quotient, Q, is equal to? : Q = 4.80 x 10-8
Q2. The molar solubility of calcium sulfite in a 0.158 M potassium sulfite solution is? : 8.23 x 10-8M
Q3. Solid cobalt(II) acetate is slowly added to 50.0 mL of a 0.0327 M potassium carbonate solution. The concentration of cobalt(II) ion required to just initiate precipitation is? : 2.45 x 10-11 M
Q4. The volume of water needed to dissolve 0.0721 grams of silver sulfate is? : 0.0143 L
Explanation
Q1. Concentration potassium sulfate = 4.80 x 10-4 M
volume potassium sulfate = 25.0 mL
moles potassium sulfate = (concentration potassium sulfate) * (volume potassium sulfate)
moles potassium sulfate = (4.80 x 10-4 M) * (25.0 mL)
moles potassium sulfate = 0.012 mmol
total volume of solution = 25.0 mL + 15.0 mL = 40.0 mL
concentration potassium sulfate = (moles potassium sulfate) / (total volume of solution)
concentration potassium sulfate = (0.012 mol) / (40.0 mL)
concentration potassium sulfate = 3.0 x 10-4 M
Similarly concentration of calcium acetate = 1.60 x 10-4 M
Reaction quotient, Q = [Ca2+][SO42-]
Q = (1.60 x 10-4 M) * (3.0 x 10-4 M)
Q = 4.80 x 10-8
When 25.0 mL of a 4.80×10-4M potassium sulfate solution is combined with 15.0 mL of a 4.27×10-4M calcium acetate solutio...
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