Question

When 25.0 mL of a 4.80×10-4M potassium sulfate solution is combined with 15.0 mL of a 4.27×10-4M calcium acetate solution does a precipitate form?   (yes or no)

For these conditions the Reaction Quotient, Q, is equal to ?

The molar solubility of calcium sulfite in a 0.158 M potassium sulfite solution is ? M.

Solid cobalt(II) acetate is slowly added to 50.0 mL of a 0.0327 M potassium carbonate solution. The concentration of cobalt(II) ion required to just initiate precipitation is ? M

The volume of water needed to dissolve 0.0721 grams of silver sulfate is ? L.(Assume no volume change upon addition of the solid.)

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CaSO4 2.4 x 10-5 PbSO4 1.8 x 10-8 Ag2SO4 1.7 x 10-5 Sulfides Cas 8 x 10-6 Cos 5.9 x 10-21 Cus 7.9 x 10-37 Fes 4.9 x 10-18 Fe
Solubility Product Constants (Ksp at 25 °C) Formula Zn3(PO4)2 K 9.1 x 10-35 Sulfates BaSO4 1.1 x 10-10 CaSO4 2.4 x 10 PbSO4 1
Solubility Product Constants (Ksp at 25 °C) Type Formula Bromides PbBr2 6.3 x 10-6 AgBr 3.3 x 10-13 Carbonates BaCO3 8.1 x 10
0 0
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Answer #1

Q1. When 25.0 mL of a 4.80×10-4 M potassium sulfate solution is combined with 15.0 mL of a 4.27×10-4 M calcium acetate solution does a precipitate form? : No

For these conditions the Reaction Quotient, Q, is equal to? : Q = 4.80 x 10-8

Q2. The molar solubility of calcium sulfite in a 0.158 M potassium sulfite solution is? : 8.23 x 10-8M

Q3. Solid cobalt(II) acetate is slowly added to 50.0 mL of a 0.0327 M potassium carbonate solution. The concentration of cobalt(II) ion required to just initiate precipitation is? : 2.45 x 10-11 M

Q4. The volume of water needed to dissolve 0.0721 grams of silver sulfate is? : 0.0143 L

Explanation

Q1. Concentration potassium sulfate = 4.80 x 10-4 M

volume potassium sulfate = 25.0 mL

moles potassium sulfate = (concentration potassium sulfate) * (volume potassium sulfate)

moles potassium sulfate = (4.80 x 10-4 M) * (25.0 mL)

moles potassium sulfate = 0.012 mmol

total volume of solution = 25.0 mL + 15.0 mL = 40.0 mL

concentration potassium sulfate = (moles potassium sulfate) / (total volume of solution)

concentration potassium sulfate = (0.012 mol) / (40.0 mL)

concentration potassium sulfate = 3.0 x 10-4 M

Similarly concentration of calcium acetate = 1.60 x 10-4 M

Reaction quotient, Q = [Ca2+][SO42-]

Q = (1.60 x 10-4 M) * (3.0 x 10-4 M)

Q = 4.80 x 10-8

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