here , i have drawn rough diagram and i tried to give complete idea.
using three rays one ray should be parallel to axis and other two should pass through focus,joining the three we get image.
i assumed height of image as h and found out height of image in terms of h. i used lens formula and magnification formula to find the image position and height of image
thank you
For each of the following descriptions: Draw the 3 principal rays to locate the image. Then, using your drawing Gi...
Diverging & Converging LENS The same object (height = y) is placed at several different distances s to the left of the same lens (focal length = f). For each case, draw the 3 principal rays to locate the image. Then use the “thin lens” equations to calculate: • the image height y' (in terms of y) • whether the image is real or virtual • the image distance from the lens s' (in terms of s and f) •...
Part A: A diverging lens has of focal length of 15.0 cm. An object is placed 21 cm to the left of the lens. a) draw a ray diagram showing the situation. b) find the location of the image produced by the lens (mind the signs). Part B: A converging lens is located 30 cm to the right of the previously mentioned diverging lens (part A). As a result, the image you found in part (a) is now instead located...
Problem 3: An object of height 2.8 cm is placed 26 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. a) Find the location of the final image, in centimeters beyond the converging lens (such that a negative answer would indicate the final image is on the same side of the converging lens as the object). b) What...
help me Question 3) An object with height 1.sotem) (the thick arrow in de converging converging lens. There is a distance from each lens to its own focal point is 15.olem diagram) is 33.0fem] to the left of a diverging lens that is 50.0[cm] to the right of the converging lens. The neha he scale is different in the vertical and horizontal directions (Be careful about sign conventions) DivergiNg Lens Converging Lens Object 1.50 cm 15.0 cm-15.0cm 15.0cm -5.0cm 33.3...
Converging & Diverging Lenses Ray Diagrams DIRECTIONS: Use at least two (2) rays (WITH DIFFERENT COLORS) to show formation of images in both converging and diverging lens. After which, identify the SOUL of the image. Note: Use different colors for the rays (10) Draw a ray diagram for a 3.0-cm tall object placed 10.0 cm from a converging lens having a focal length of 15.0 cm. 2f 2f (11) Draw a ray diagram for a diverging lens that has a...
3. Figure shows an object and its image formed by a thin lens. (a) What is the focal length of the lens and what type of lens (converging or diverging) is it? (b) What is the height of the image? Is it real or virtual? Draw a principal-ray diagram showing the formation of the image. -35.0 cm- Optic Object 15 Lens El crn Image 4. Figure shows an object and its image formed by a thin lens. (a) What is...
All the details I have been given. NO more info provided!!! For each of the following diagrams: Draw the 3 principal rays to locate the image. Then, using your drawing Give the image height in centimeters Give the image distance from the lens in centimeters First: use a ruler to determine the focal length in centimeters. You can use this information to help you estimate the size and location of your images f cm 1) S=2f It this image real...
Use the thin lens equation to solve problems 14 –18. 14. An object is 10 cm high and is placed 20 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 15. An object is 10 cm high and is placed 16 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 16. An object is...
An object of height 2.8 cm is placed 27 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length.Part (a) Find the location of the final image, in centimeters beyond the converging lens. Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object.
Part A: A diverging lens has of focal length of 15.0 cm. An object is placed 21 cm to the left of the lens. a) draw a ray diagram showing the situation. b) find the location of the image produced by the lens (mind the signs). Part B: A converging lens is located 30 cm to the right of the previously mentioned diverging lens (part A). As a result, the image you found in part (a) is now instead located...