Question

wist the products formed from the following metathesis reactions and write out balanced molecular, lonie and net lonie reactions, A) lithium carbonate(aq) calcium sulfate(aq) → B) lead (II) nitrate (aq) + sodium iodide (aq) → 3) A 10.00 gram gas mixture contains Na and CO2. If 2.00 grams of the mixture is Nz and the total pressure of the mixture is 2.00 atm, what is the partial pressure of nitrogen gas?

Answer 1

I AY Balanced equation. Lig CO₂ (aq) + Caso4(aq) Lithium calcium Carbonate sulfate Ionic equation. caco₂(6) calcium carbonate 4,504 Lithium sulfate ..22,+ Loco Cacoa 3 (5) 221 + 504 lag) cag). 2 lit + cog²- + ca 2t 50% I cag) cag) caq) caq ? Net ionic equation. Ca2+ + cos CaCO3 cag) caq) (6). B> Balanced equation. Pb(NO3), cag) 2 Na I (ag) Lead Nitrate Sodiumjodide PbI2 (6) + 2 Nanoz Tag). leadiodide sodium nitrate p62+ ca Ionic equation. NO- 2rat 21 JPGI2 + 2NOT + 2No.- It can cag) cag (6) cag) one Net ionic equation. Pb2+ + 210 - Pb Iz (6) cago cao)

③ Firstly calculate the mole fraction of the mixture. We have 10.00 g mixture contain N2 and co2 and Ng = 2.00g .. mass of coq = 8.00g. gas. .. No. of moles of No given mass molar mass 2.00g 28.00 gimo). -0.0714 mol. No. of moles of co2 given mass 8.00g - molar mass - 44.00 g/mol -0.1818 moll :: Mole frachion Of N2 0.0714 0.0714 -0.0716 tovere -0.22 0.0 0 mole fraction 0.1818 0.1818 0.700 of co2 -0.1818+0.0716 = 0.2535 -0.118 (Xcop) mole fraction of the mixture will be. X-XN2 + Xeo2 = 0.282 +0.718 = 1

. The partial calculated as pressure of Nitrogen gas can be Given, X = 0.282. Poral = 2.00 atm. 0.282 x 2.00 alm. P = 0.564 arom] 0.564 arm.