Question

Problem 4: Two blocks are traveling toward each other. The first has a velocity of 5 m/sec and the second a velocity of 9 m/sec. After the collision, the second block is moving with a velocity of 4 m/sec in a direction opposite to its initial velocity. If the mass of the first block is trice (3 times) that of the second, determine the following: - The velocity of the first block after collision; - Whether the collision was elastic or inelastic.

Answer 1

Dvos VO, JoseO ma = 3m2 001 m2 from compervation of momentum of system ma Vol - M2 Vo2 = mas + m2 V2 3m2 (5m/s) – m2 (900/S) = 3m2 Vq + m2 (4m/s) - 15 ms - gm/s = 3Vq + 4 m/s → 3V1 = 2ms >> Ug = 0,66 mis Fritial Remetic energy of system ki = 1 m a Vog ² + 2 m 2 V 2 2 Kis 1 300)2 ( 5m/5)2 + 5 m2l-gm/s)2 ki = 156 m2 = 78m2 Final Kinetic energy of system Kf = 2 m2 V, 2 + / m2 V₂2 KA2 L 2 [3x ($m/s)? + 4400 15)?] Kf = 8.67 m2 Since Kf<ki collbion us inelastic.