Question

A loaded beam with a pin support at B and a rller support at C is shown in Figure 1. The applied loads on the beam are: an anti-clockwise point moment at A, a variably distributed load between B and C, and a clockwise point moment at D g kN/m f kNm h kN m A C 4 m 2 m 2 m Figure 1 The magnitude of the anti-clockwise point moment f in units of kN'm can be found by summing the 1, 2nd and 3d digits of your student number The magnitude of the variably distributed load gin units of kN/m over support B is equal to the sum of the 1st, 2nd, 4th and 5th digits of your student number. The magnitude of the variably distributed load over support C is 0 kN/m. The magnitude of the clockwise point moment h in units of kN'm is equal to the sum of the 1, 2n, 6th and 7th digits of your student number. For example, if your student number is: [1]17][6][1][2][3][4] Magnitude of the anti-clockwise point moment fis equal to 1+7+6 14 kN'm Magnitude of variably distributed load g is equal to 1+7+1+2 = 11 kN/m Magnitude of the clockwise point moment h is equal to 1+7+3+4 15 kN*m A loaded beam with a pin support at B and a roller support at C is shown in Figure 1. The applied loads on the beam are: an anti-clockwise point moment at A, a variably distributed load between B and C, and a clockwise point moment at D g kN/m f kN°m h kN m A B C 4 m 2m 2 m Figure 1 The magnitude of the anti-clockwise point moment f in units of kN'm can be found by summing the 1, 2nd and 3d digits of your student number. The magnitude of the variably distributed load gin units of kN/m over support B is equal to the sum of the 1st, 2nd, 4th and 5th digits of your student number. The magnitude of the variably distributed load over support C is 0 kN/m. The magnitude of the clockwise point moment h in units of kN'm is equal to the sum of the 1, 2, 6h and 7th digits of your student number For example, if your student number is: [1]17][6][1][2][3][4] Magnitude of the anti-clockwise point moment fis equal to 1+7+6 14 kN'm Magnitude of variably distributed load g is equal to 1+7+1+2 = 11 kN/m Magnitude of the clockwise point moment h is equal to 1+7+3+4 15 kN*m DETERMINE THE FOLLOWING: 1) Compute the reactions at supports B and C. 2) Determine the shear force equations for all segments of the beam if the datum used is Point D (right end of the beam). Please express all equations in decimal format (no fractions). Marks will be deducted for equations that use Point A (left end of the beam) as the datum 3) Hand draw the shear force diagram and annotate the values at positions A, B, C and D. 4) Identify the location on the beam between the supports at B and C where the Shear Force is 0 kN. The location should be relative to the datum at Point D. 5) Determine the bending moment equations for all segments of the beam if the datum used is Point D. Please express all equations in decimal format (no fractions). Marks will be deducted for equations that use Point A as the datum. 6) Hand draw the bending moment diagram and annolate the values at positions A, B C and D 7) Identify the magnitude of the bending moment and the location on the beam between the supports at B and C where the bending moment has a local maximum. The location should be relative to the datum at Point D 8) Use SkyCiv to analyse the beam (exactly as i is shown in Figure 1) and draw the shear force and bending moment diagrams. Refer to the following page for SkyCiv output instructions

Answer 1

14kN-m AGT 1s kN-M tm 2n 1442kN 7583KN 14.422の チve o. SFD. ve 7.583 kN calculation o Reactions:- EMB 15+Ix4x -14-Rex4 o RC 7.58 kN Fy so XIIX4758 - RB-0 Re= 14.42kN

eshear force 9uakon for segment CD O SF for segment Bc= -758+x2-2 2 -211 11 -7.38 2 S.F for segment AB-758 +y (-2) x- Shear force equation for Jeg ment BC 70 IL Cx-2)-7.58 O 758x8 7 2 435 m from D. at 4.35 m frDm D. 0 The shearforce is zero