Question

3. (40 pts.) Consider the following parallel reactions that we have encountered in producing the desired product B at 300 K FF rB kiCA 0.0015 CA (1) A B (2) A C rc k 0.0001 (3) A D : rD kCA 0.008 CA The reactions are in liquid-phase. The activation energies of the reaction (1), (2), and (3) are 5x 104 kJ/mol, 4x10 kJ/mol, and 8x10 kJ/mol, respectively. We want to know how and under what conditions the reaction should be carried out to maximize the selectivity of B for an entering concentration of A of 0.4 M and a volumetric flow rate of 2 L/s. Answer the following questions: (a) Find the selectivity of B as a function of the concentration of A, and sketch a plot of the instantaneous selectivity of B vs. CA (b) Find the maximum instantaneous selectivity of B, and the corresponding CA to maximize the selectivity of B? And, why is that so? (c) Which reactor would you use (d) Calculate the volume of the reactor chosen in (c). (e) Calculate the conversion of A in the reactor chosen in (d). (f) Calculate the overall yield of B in the reactor chosen in (d). (g) What CB, Cc, and Co in the exit stream of the reactor chosen in (d)? are (h) Suppose that we aim to maximize the concentration ofB in the exit stream. Do we need to make any change(s) when using the reactor chosen in (c)? If so, provide the required change(s) and find CB. (i) Provide any suggestion to increase the conversion of A by attaching additional equipment(s). (i) If we have a freedom to choose the operation temperature, what would you do to maximize the selectivity of B? And, why?

we can find the type of the reactor at problem no.(c).

Answer 1

Please go through the explanation.
niven Que3 E, - SXIO KI) mo Ezc47101KImo A C (2) cK2 o.000 A D (3) DE 3Cn2: 0.008 CA E2= 87104K)ma) CAo-0.4 o 2 L)s R9te equahion of desized product B SelcD Pate equaH'on of und esik,ed prakit (0+P) O.o015 CA o.0015(A 2. O 0001 +0.o08 Ca Y0.1875 CA SB Sope= o1875 CA SB O O015CA Cb) CtD Oroo 008(A2 dCA dgceo (o.00010.008(A)yo,0015 -010015CA ( E X 0 1008 (aJ 0.000lto,008 (A 0 000012 CA2 o.0000 0 O1-o. oo 00za CA o 0 0000120A2= 0.000o015 2. . CA =0.0 /25 O.li180 vo 1t :a"IbA 1nd ) uoHbhba u o 0.8385

O ugydnba wolp o O015 CA SB D O.008CA2 CA 0008 CD Sel ecHvity Ond Po loo concenth qHon Sti'Aged tomk heactos (CSTR). fon maximmize the s Concenthahon of A heguifec we used Continuous Cd) oe kmouo theF -TA o.0O 1S CAt o.001+ o.00 8 CA2 for CSTR CAECAOLI-XA) CAOTA= CAo-CA CAOXA てこと= Vo reto (CAo-CA) V - o0015(A + 0.000l + O.008 CA 2 op O.4-0.112 80 Vo O 0015x011180-+0.00 01 O1008x (0'l180) 2- o. 2882 Oo 00367693 9 Y 783.804) 78 3.8041 X 2 Y 1567 608 2 Convession im STR ce) CA CAO I-A) -) o.111S0 - 0,41-Y) 5

Rete eq" of dekihed pruduct B oveh91 yield R9te ean of 4egutamE A O.O015 CA 0.008 CA O O015 CA o1000 Put CAO180 o.45606 3 foh CSTR CB -Bot CB0.45608(0.4- o'118 B0.13144 M 0 008 CA2 O, o 00 0. 0015 CA pu ECAZOU Eo.2719 65 Ce 0.2719 6 5 x (0.4- 0 80) Oroo8CA 2 OI0015CA+ O 0001000B(42 Yg=< -0.2719 487 Cp o.27194 87 x (o14-0ill1So Co 01078375M

Ch) The qctivation eneajy of product B i moke thyr C bu Poaduct D, so foh marimizing the (oncentaghon of B Aequised less tempek9 tuk e. zhe (onent4ghon of B en (a1e 191ed past equ ihed TR Foh inchegse the conveg sion of A oe A for mormne the selectvity ess opes 9 Hng tempesgtu4e OP B Aeguiked we