Homework Answers
Answer: (a) The frequency of the genotype (aa) is 260/5000 = 0.052
Thus, q2 (or the genotype frequency of the recessive trait) is 0.052. Therefore, the frequency of the recessive allele a in the population is (0.052)1/2 =0.228
(b) Since p + q =1 or p= 1 - q. Therefore, the frequency of the dominant allele A = 1 - 0.228 = 0.772
Genotype frequency of the homozygous dominant trait (AA) is p2 or (0.772)2 = 0.544
Thus, the proportion of the population that is homozygous dominant for this trait is 0.544
(c) The genotype frequency of carrier individuals = 2pq that is, 2Aa
Therefore, 2Aa = 2*0.772*0.228 = 0.352
Thus, the proportion of carrier animals in the population = 0.352 * 5000 = 1760
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