Question

Let u and v be the vectors shown in the figure to the right, and suppose u and v are eigenvectors of a 2 x2 matrix A that cor

10- T(v) T(w -10 10 T(u) -10- Ay 10- T(v) T(w) T(u) 10 10 -10- 41

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Use a property of determinants to show that A and AT have the same characteristic polynomial. NONE Start with det (AT-Al)-det
Let u and v be the vectors shown in the figure to the right, and suppose u and v are eigenvectors of a 2 x2 matrix A that correspond to eigenvalues -2 and 3, respectively. Let T: R2 R2 be the linear transformation given by T(x)-Ax for each x in R2, and let w-u+v. Plot the vectors T(u), T(v), and T(w). 2- u -2 2 4 -2
10- T(v) T(w -10 10 T(u) -10- Ay 10- T(v) T(w) T(u) 10 10 -10- 41

Use a property of determinants to show that A and AT have the same characteristic polynomial. NONE Start with det (AT-Al)-det (AT-AIT) = det(A-Al)T. Then use the formula det AT-det A. Start with det A1( -1 ) det AT. Then use the formula AAT I. Start with det (AAT). Use the formula det AB (det A)(det B) to write det (AAT) (det A)(det AT). Then use the formula AAT-1
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Answer #1

Dace: Sin ce uis eigen veuto conapenoing ?-2 -2 L T(u) A4= Simlaly TIV AV -3V 3 eiavectes V TW) -2u 3V in Ce TU1E-6-2 T(v)= 6

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