48.64 50. 91 57.94 58.89 Mass of large test tube Mass of test tube with acetic...
i cant figure out #8 please help. thank you. also if you could help with #6 it would be greatly appreciated CALCULATIONS Show all work. 1. Mass of acetic acid, g 19.66g 2. Mass of unknown sample in acetic acid solution.g 2.00 g 3. Generate a cooling curve by plotting temperature vs time data on a single graph Plot on graphing paper or use a computer program and print plot. See Below 4. Freezing point of pure acetic acid solvent...
A. Freezing Point of Cyclohexane (Solvent 1. Mass of beaker, test tube (g) 2. Freezing point, from cooling curve 3. Instructor's approval of graph 33010 B. Freezing Point of Cyclohexane plus Unknown Solute Trial 1 Parts B.1, B.3) Unknown solute no. Trial 2 (Part B.4 Trial 3 Part B.5 1. Mass of beaker, test tube, cyclohexane (g) 2. Mass of cyclohexane (g) 3. Tared mass of added solute (g) 4. Freezing point, from cooling curve CC) 5. Instructor's approval of...
U SR, test tube, apparatus, cyclohexane 2. Mass of flask, test tube, apparatus 3. Mass of cyclohexane 4. Freezing point, from cooling curve 203.239 g 7.9079 5.9°C B. Freezing Point of Cyclohexane plus Unknown Solute Unknown Solute Trial 1 Trial 2 Trial 3 1. Mass of cyclohexane 1.9029 8.152 8.40ly 2. Mass of solute, total Bolby 8.409 9.5989 3. Freezing point, (cooling curve) 1.8 C 2C 7°C 20° 7.9079 Calculations 1. K, for cyclohexane (pure solvent) 2. Freezing point change,...
for question 1 the molar mass of unknown is 102g/mol hation by Freezing Point Depression Vernier Logger Pro for Windows Section Post-Laboratory Questions (Use the space provided and additional paper if necessary. Record your nemerical answers in the boxes provided.) 1. Obtain the correct molar mass of your unknown from your laboratory instructor. Calculate the percent error in the molar mass that you found. Torg/mol percent error, 2. A student determined the freezing point of pure t-butyl alcohol following the...
Need help with freezing point depression expeiment volume of acetic acid 30 volume of unknown solute in solution1 1.5 volume of unknown solute in solution 2 1.5 freezing point of pure acetic acid 16.3 freezing point of solution 1 14.5 freezing point of solution 2 11.3 average molar mass of unknown solute Calculations for Part 1 The density of acetic acid is 1.049 g/mL and Kf(acetic acid) =3.90 °C·kg/mol The density of the unknown is 0.791 g/mL. 1.Calculate the masses...
Equilibrium Fe 3+ Given the following information what is the concentration of SCN * at equilibrium? Ko = 450, Fe 3+ is 4.9 x 10-3M and Fe(NCS) 2+ is 1.8 x 10-4 M. The equilibrium reaction is: + SCN 5 Fe(NCS) 2+ a. 8.2 x 10-5 b.4.0 x 10-4 O c. 1.2 x 104 d. 17 e.6.0 x 10-2 Pure glacial acetic acid, HC2H302, has a freezing point of 16.62 °C. Its freezing point depression constant is: Kf = 3.57...
A. Data Test tube mass + glass + water: 84.74g Test tube mass + glass: 41.93g water mass: 42.81g mass of water in kilograms: 0.04281kg sacrose mass: 5.00g Kf water: 1.86C/m B. Graph data A: pure water cooling curve minutes with temperature 0minutes: 20.0C 1 minutes: 3.0C 2 minutes: 3.0C 3minutes: 1.0C 4minutes:1.0C 7 minutes:1.0C 8 minutes: 0C 11 minutes:0C 12 minutes:0C 13 minutes:-1C 14 minutes:-1C 15 minutes: -1C C. Graphic data B: solution cooling curve (sucrose and water) minutes...
A solution made by dissolving 85.0 g f sucrose (Molar mass. 342.3 g/mol) in 515 go acetic acid at 25 degree C froze at 14.95degreeC. Freezing point of the pure acetic acid is 16.90degreeC.Density of acetic acid is 1.05 g/ml. at 25 degree C. Answer the following and show your work in the space provided. Molality of sucrose solution = K_i of acetic acid = 93.42 g of an unknown non-volatile, non-electrolyte solute was dissolved in 850.g of acetic acid....
When 12.6-grams of an unknown compound is placed in 0.116-kg of benzene, the freezing point is changed by 2.34°C. The value of Kf= 4.90°C/m for benzene. Determine the molar mass of the unknown compound. Answer to 1 decimal place and include your units. Answer: Determine the molality of a solution when 32.3 grams of ethanol, C2H5OH (Molar mass = 46.08 g/mol) is dissolved in 0.947 kg of water. Answer to 2 decimal places. Answer: Find the freezing point of a...
Date Name Lab Section Partner(s) Determination of Molar Mass by Freezing Point Depression Data: Mass of empty test tube 2.2.6! Mass of test tube plus approximately 10.0 g of benzophenone 33.39 The difference is the mass of benzophenone (solvent) 8 kg Mass of unknown (-1.0 g) 1:09: 48.50°c 42.08. Freezing point of pure benzophenone Freezing point of benzophenone containing the unknown The difference is A fp CO Calculations: (Show set-up with cancellation of units) 1. molality of solution 2. moles...