In a solution of the weak acid DNP (pKa 4.11) in water, [H3O+] = 9.4 x...

Question

Question

In a solution of the weak acid DNP (pKa 4.11) in water, [H3O+] = 9.4 x 10^-4 M and DNX, the conjugate base, has a concentration of 0.00180 M.

A.) What is the concentration of DNP in the above solution?

B.) What is the pH of the solution?

Answer 1

Answer #1

(A) This is a buffer of DNP and DNX, so we can use Henderson- Hasselbalch equation as follows: - pH = pka + log [DNX =) =log

Comment in case of any doubt.

Answer 2

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