Question

Ex 3 3-phase network. Un= 15 kV (take it in point 0), S=35 mm7, y= 34 m/(Q-mm2), X'-0,4 Q/km. L01 L12 23 2 2 13 Length of lines: L23 4,2 km L12 800 m Lo1 2,5 km, Load currents: 38,5-8,1 A, 2 44,8-18,1 A a 25,4 j4,1 A. Calculate: Total voltage loss SU03 [V] ? (complex number!) Total voltage drop Δυ03 [V] ? AP03 Total active power loss [W] ? Total reactive power loss [var] ΔQ03 ?

Answer 1

Si-3 UN=ISKV Sio- Sec3 V Spt2 in arendeth 2 35mm adectrocity 3um) WeAnw that R= GA Total bngth 85+08ナ4-2:フ5m そ1000 ef tondueth per km- :Resistan 3513u 0,84033A/km .hiven heactanct- Ou N /km. Tmmdnet perkon 0.8403 tJ0 ^/km. E 38.5-jg)フ= 44-8-j1s-1; T3=25.4t4ol 08.7-22.1 2.ip075+1に201 212 (0.8u83 to8 0b7zzu t032 Tmadnee Inprdnce LIz Section /23 section(o Suo3 +jou)2 = 3.529t68 Cwnent in ser-3 - 万-9Gu+l) E57a/2-16 Cwmut in Ser-a *Zzナ五ー 702ー14i Clopu vt in Set-t,+7,4,)-I30is fos.1-22.1J 7/. 27

The и бадра рч вндоте sdapn - I5a1-108.7-22A)a 12.0 75+ i) -/7w1-ki)# to32 (25-4 +i) (3.529414 at ly6-71-.52 J46-1924.61-0-1821 ( 14.6151-05772 UN heceiwing Sendin Take os 0.38ys8t 013246 0.y07039/13.99 (active powth Active Powh lossis ou to esistance 2 Pss3R,+ 3+/ 3) Rz3 BrlasZe 3*(+5)X2+3*lZ,)* X»2 3r (7-3)ro biany Phy-3*(t.9i75 + +3* 3 316ay 89 94874.9093 24.87kp 2- 5635 ys1bkVA