Question

Ex 3 3-phase network. Un= 15 kV (take it in point 0), S=35 mm7, y= 34 m/(Q-mm2), X'-0,4 Q/km. L01 L12 23 2 2 13 Length of lines: L23 4,2 km L12 800 m Lo1 2,5 km, Load currents: 38,5-8,1 A, 2 44,8-18,1 A a 25,4 j4,1 A. Calculate: Total voltage loss SU03 [V] ? (complex number!) Total voltage drop Δυ03 [V] ? AP03 Total active power loss [W] ? Total reactive power loss [var] ΔQ03 ?

Answer 1

1 S01! I3 T+エ3 IitIrtIz 3 2 I3 Iz Given data UN -15KV ( line-line) 15 8.66 KN II 38.5-j8.1 A 44.8-j18.1 A 95.928 (9.169 A 95.4+j4.1 A 10.923/-11.49A (108,7-jaa A ル582|1-228A 2-J)A Ka-mm) 34m Y Conductavity) S=35mm 2.5 KM 80Dm st4.2 km QO.5x103 Ro 35 x 34 S.Y

X'X t 14% O.uxg.5 80D O.6792 S12 Ri2 35*34 O.39 0.4x 6,8 1 4.2X108D 3.529 S23 Ra3 35 *34 S.Y .68n O.4 x 4.2 422 Ph -CH-j23.)(2. j]2-j jo3) C.6722 'jiw] C54tjy3.529+ (384.787 tj 132.484)V 21

Total Voltage lol Ph voltage - drop 1 CAfteY chop) (8.66x 16')-(384787jmaun) (8275 212-j 132.u)v Total Active Power los 3- PoueY los 3x 3. PA37 3x C1041:3), 3. RI.58 3x25.7 3x a5.728x 3.S29] 94.855 kW Total Yeautive Pouoer los => 3-6 los (3x Ty% K2s) C 3x25.120% 1.t) 45.166 KVAR 1