Question

4/15/2019 Prieto 13. According to a certain government agency for a large country, the proportion of fatal traffic accidents in the which the driver had a positive blood alcohol concentration (BAC) is 0.39. Suppose a random sample of 103 fatalities in a certain region results in 52 that involved a positive BAC. Does the sample evidence suggest has a higher proportion of traffic fatalities involving a positive BAC than the country at the 0.05 level of s c (1) - -10, the sample size is (2) 5% of the satisfied Because np. (1-P) - population size, and the sample (3) (Round to one decimal place as needed.) What are the null and alternative hypotheses? the requirements for testing the hypothesis (6) versus H, Ho: (5) (5) (7) (Type integers or decimals. Do not round.) Find the test statistic, 20- Zo = (Round to two decimal places as needed.) Find the P-value. P-value = (Round to three decimal places as needed.) Determine the conclusion for this hypothesis test. Choose the correct answer below. A. Since P-value <a, do not reject the null hypothesis and conclude that there is not sufficient evidence that the region has a higher proportion of traffic fatalities involving a positive BAC than the country B. Since P-value <a, reject the null hypothesis and conclude that there is sufficient evidence that the region has a higher proportion of traffic fatalities involving a positive BAC than the country. O c. Since P-value >, do not reject the null hypothesis and conclude that there is not sufficient evidence that the region has a higher proportion of traffic fatalities involving a positive BAC than the country D. Since P-value >, reject the null hypothesis and conclude that there is sufficient evidence that the region has a higher proportion of traffic fatalities involving a positive BAC than the country. O (1) O (2) less than greater than (3) (4 0 can be reasonably assumed to be random cannot be reasonably assumed to be random, is given to be random, O is given to not be random, are not are (5) OO (6) OK (8) O * VA o Ea Oooo

can i please have the answer explained with the ti-84? thanks!

Answer 1

Solution:

Print Questions 13. According to a certain government agency for a large country. the proportion of fatal traffic accidents in the which the driver had a positive blood alcohol concentration (BAC) is 0.39. Suppose a random sample of 109 fatalities in a certain region results in 52 that involved a positive BAC. Does the sample evidence suggest has a higher proportion of traffic fatalities involving a positive BAC than the country at the 0.05 level of sg Pue evidence suggest that the region Because npo (1-P) - 25.9311 (1) = 10, the sample size is less than 5% of the population Size, and the sample (3) is given to be randomb the requirements for testing the hypothesis (4) l are satisfied. (Round to one decimal place as needed.) What are the null and altemative hypotheses? Ho: (5) P (6)_ 0.39 versus H, (7) 0.39 - (8) (Type integers or decimals. Do not round.) Find the test statistic, Zo- 20 = 1.86 (Round to two decimal places as needed.)

Find the P-value P-value = 0.031 (Round to three decimal places as needed.) Determine the conclusion for this hypothesis test. Choose the correct answer below. A. Since P-value < do not reject the null hypothesis and conclude that there is not sufficient evidence that the region has a higher proportion of traffic fatalities involving a positive BAC than the country B. Since P-value <a, reject the null hypothesis and conclude that there is sufficient evidence that the region has a higher proportion of traffic fatalities involving a positive BAC than the country. C. Since P-value> , do not reject the null hypothesis and conclude that there is not sufficient evidence that the region has a higher proportion of traffic fatalities involving a positive BAC than the country. D. Since P-value > a, reject the null hypothesis and conclude that there is sufficient evidence that the region has a higher proportion of traffic fatalities involving a positive BAC than the country. The steps to be followed in Ti-84 Press STAT and then scroll right to TESTS Then scroll down to 1-PropZTest... Then scroll right to stats Enter the values as: 1-PropZTest PI:.39 X:52 n: 109 Propipo (Po >PO Calculate Draw O The output is: 1-PropZTest FroP613049 P=.6311879687 =.4770642202