here,
let the diameter is d2
change in pressure = p * g * h
0.50 * 1000 * (v2^2 - v1^2) = 1000 * 9.8 * (0.05)
Now,
v1 * A1 = v2 * A2 = volume flow rate
pi * (0.0273/2)^2 * v1 = 1.68 *10^-4
v1 = 0.287 m/s
putting in equation 1
0.50 * 1000 * (v2^2 - v1^2) = 1000 * 9.8 * (0.05)
0.50 * 1000 * (v2^2 - 0.287^2) = 1000 * 9.8 * (0.05)
v2 = 1.037 m/s
Now, for the diameter d2, using equation of continuity
pi * (d2/2)^2 * 1.037 = 1.68 *10^-4
d2 = 0.0144 m = 1.44 cm
the diameter of the narrow section is 1.44 cm
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