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m/s. Determine the inside diameter of the The inside diameters of the larger portions of the horizontal pipe depicted in the

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usi ing Bernoullis equation, eott egh = ent a tegn huyu+gh = y + gn lo e = K2 +gHugh Vg2 = a (v + 3C#-n).2) ve Svit og cv-h)4x 1.70 x 106 m3/ тх (2.ос жібъ)-as v= 0.57 m/s And H= 10x10²m = Oolm And h= 5x10 m = 0.05m m - 0.05m .: Ve 1(0.57m/s]+2x9.8 m/3 (oom - 0.05m) o= [0.3249 m/oInside diameter, d = 14B 1 V TO 3 d = 4x 1.900 104 m/s v T x llum/ - d = 0.01457 m cool d= 1.457 cm

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