Question

help with percent calculations in sand salt and ammonium chloride lab

Partner's Name SAMPLE ID. BAY (1 pt) Mass of Evaporating Dish 58.273 a (3 pts) Mass of Evaporating Dish and Sample_60.5588 (3 pts) Mass of Sample 2.2854 (4 pts) AMMONIUM CHLORIDE Mass of Evaporating Dish and Sample..... After First heating 60.4689 (2 pts) After Second heating 60.466d (2 pts) After Third heating (if necessary) Mass of ammonium chloride 0.088. (3 pts) Using the lowest mass measured, calculate the mass of ammonium chloride that sublimed into the air. Show your work. (5 pts) 60.4685-60.4 669= .0029 goog .002_ *100 = .0875% 2.285 -0.088%. SAND Mass of Filter Paper 1.2419 (3 pts) Mass of Filter Paper and dried Sand 2.5940 (3 pts) Mass of Sand (4 pts) SODIUM CHLORIDE 141-8699 Mass of Flask 7.410 (3 pts) Mass of NaCl and Flask 142.8749 (3 pts) 1.0059 Mass of NaCl (4 pts) Describe the physical appearances of the three components, sand, sodium chloride and ammonium chloride after each was separated from the mixture. (5 pts) The ammonium chloride evaporated into a white colored gas. The sait looked like Crystals after seperation

Answer 1

Percent mass of ammonium chloride = [(60.468 - 60.466) / 2.285 g] x 100% = 0.09 %

Percent mass of sand = [(2.594 - 1.241) / 2.285 g] x 100% = 59 %

Percent mass of sodium chloride = [(142.874 - 141.869) / 2.285 g] x 100% = 44 %

Sum of percent masses = 0.09 % + 59 % + 44 % = 103.09 %

Hi Dear, i just did calculation based on your input, it seems to be some error present as sum of percent masses should be always = 100 % only, but you got 103.09 % this means additional 3.09 % should be deducted from any of the sample and then show it to your professor!

Hope this helped you!

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