Assignment Score: 233/2000 Resources Hint Check Answer Question 16 of 20 Consider the reaction 2 Pb(s)...

Question

Question

Answer 1

Answer #1

Given balanced reaction is 2Pb(s) + O2(g) ----> 2PbO(s)

Molar mass (g/mole) 207.2 32 223.2

From the above balanced reaction,

2 moles = 2*207.2g = 414.4 g of Pb reacts with excess of O2 produces 2 moles = 2*223.2g = 446.4 g of PbO

451.4g of Pb reacts with excess of O2 produces M g of PbO

M = ( 451.4g*446.4g) / 414.4g

= 486.3 g

This is the theoretical yield(486.3g)

But given that the actual yield is 319.3g

So percentage yield = ( actual yield/theoretical yield)*100

= ( 319.3g/486.3g) *100

= 65.7 %

Therefore the percentage yield is 65.7%

Answer 2

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