velocity if particle
v = at = 2.4* 10^7* 5 = 1.2* 10^8 m/s
relativistic momentum
P = m v / sqrt (1 - v^2/c^2)
P = 2.7* 10^-28 * 1.2* 10^8 / sqrt ( 1 - (1.2 / 3)^2)
P = 3.535* 10^-20 kgm/s
de broglie wavelength
L = h/ P = 1.877* 10^-14 m
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A particle (m = 2.7 * 10-28 kg) starting from rest, experiences an acceleration of 2.4...
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A particle (m = 3.0 × 10-28 kg) starting from rest, experiences an acceleration of 2.4 × 107 m/s2 for 5.0 s. What is its de Broglie wavelength λ at the end of this period?
A particle (m = 2.7 × 10^-28 kg) starting from rest, experiences an acceleration of 2.4 × 10^7 m/s2 for 5.0 s. What is its de Broglie wavelength λ at the end of this period? Please help, I understand that v=at so you need to do 2.4 multiplied 5 and I got 12. Meaning v=12x10^7 Then I did h/mv which is (6.626x10-34)/(2.7x10^-28*12x10^7) and I finally got 2.045x10^-14 but this is still wrong and I don't understand why.
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