Question

7. A 4.37 gram sample of a certain diatomic gas occupies a volume of 3.00-L at 1.00 atm and a temperature of 45°C. Identify this gas. A) F2 B) N, C) H D) 02 E) ci,

Answer 1

Date:- Page: PV=nRT P₂ Pressure tatm) na moles R = 0.0821 gas constant Ta temperature (45+273-15) = 318-15K V = volume = 32 n= PV RT n = ( 1) (3) (0.0821) (318.15) 0.114 moles n - 4.37g 0.114 moles = 38.03 g/mol Malesz May (9) Molar mass (g/mol) Molar mass z man = moles The gas is f2 ② Ansmen Ans med