Question

* Amass of 2.0 kg is connected to a spring with a spring constant of 5.0 N/m. The mass is oscillating on a horizontal, frictionless surface. At time t = 0, the mass is 0.30 m from the equilibrium position and has zero velocity. (a) What is the amplitude? (b) What is the maximum speed of the mass? (c) What is the maximum acceleration of the mass? (d) Write an equation that describes the displacement of the mass from the equilibrium position as a function of time. (e) Write and expression if the mass is at 0.10 m at time t = 0 (nothing else changed).

Answer 1

u tu osplacement q eu was be the following equation alt) A cas (wt + p) v dx = -Aw si Cotto) here, we slym - 5/2 Ginem at t=0, x 10) = 0.3 Also at to (o) 0 0.3= A coso 0 -Awrung -0 - & Asinp=0 a) squaring and adding both A - 0.3² tot [A-0.3m ] druiding both, we get taupo apo act) - 0.3 cos (w) y X(t) = 0.3 cos (172-t) 7 1) ма уште о м и шля - Au Juan 0.3 x 15 ohщ 44 ost if Juny 0.474 ms l a caccelesation, de - Aw² casuot . Qmax - Aw = 0.3x5 laman : 0.75mler e) it at t=0, x 10) = 0.1 - A - Olm & similarly 8-0 Rest all are done sinularly Vmax 0.158 ml amaya 0.25 m/s²