A block of mass 0.21 kg connected to a spring with spring constant 37 N/m is...
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A block of mass 0.21 kg connected to a spring with spring constant 37 N/m is oscillating on a frictionless horizontal surface. Its speed as it passes through its equilibrium position is 0.88 m/s. What is the total energy of the system in J? |
Homework Answers
At equilibrium position, potential energy is 0 and there exist
only kinetic energy
Total eenrgy = potential energy + kinetic energy
= 0 + 0.5*m*v^2
= 0.5*0.21 * 0.88^2
= 0.081312 J
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