The reaction between iron(II) ( Fe2+ ) and dichromate ( Cr2O2−7 ) in the presence of a strong acid ( H+ ) is shown. Cr2O2−7+6Fe2++14H+⟶2Cr3++6Fe3++7H2O Determine the volume, in milliliters, of a 0.180 M solution of Mohr's salt ( (NH4)2Fe(SO4)2⋅6H2O ) needed to completely react with 0.0500 L of 0.180 M potassium dichromate ( K2Cr2O7 ).
volume? ... mL
What volume, in milliliters, of 0.180 M K2Cr2O7 is required to completely react with 0.0500 L of a 0.180 M solution of Mohr's salt? volume? ... mL
Cr2O7^2-+6Fe2++14H+⟶2Cr3++6Fe3++7H2O
1 mole 6 moles
( (NH4)2Fe(SO4)2⋅6H2O ) K2Cr2O7
M1 = 0.18M M2 = 0.18M
V1 = V2 = 0.05L = 50ml
n1 = 6 n2 = 1
M1V1/n1 = M2V2/n2
V1 = M2V2n1/M1n2
= 0.18*50*6/(0.18*1)
= 300ml
The volume of (NH4)2Fe(SO4)2⋅6H2O ) = 300ml >>>answer
The reaction between iron(II) ( Fe2+ ) and dichromate ( Cr2O2−7 ) in the presence of...
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