Question

Part a please. Both screenshots are of previous wrong answers.

Results for this submission Entered Answer Preview Result (0,0), (5000,100), (10000,0) (0, 0), (5000, 100), (10000, 0) incorrect -0.3L+0,0004AL (-0.3 L+0.0004 A'L3 A correct (1-0.00025 A)-0.04 A"L] 3A(1 0.00025A) 0.04AL At least one of the answers above is NOT correct. (3 points) A previous exercise modeled populations of aphids and ladybugs with a Lotka-Volterra system. Suppose we modify those equations as follows: dA -3A(1 0.00025A) dt dL =-0.3L + 0.0004AL dt - 0.04AL (a). Find the equilibrium solutions. Enter your answer as a list of ordered pairs (A, L), where A is the number of aphids and L the number of ladybugs. For example, if you found three equilibrium solutions, one with 100 aphids and 10 ladybugs, one with 200 aphids and 20 ladybugs, and one with 300 aphids and 30 ladybugs, you would enter (100, 10), (200, 20), (300, 30). Do not round fractional answers to the nearest integer Answer (0, 0), (5000, 100), (10000, 0) (b). Find an expression for dLUdA. dL dA (-0.3L+0.0004ALM3A(1-0.00025A)-0.04AL] (3 points) A previous exercise modeled populations of aphids and ladybugs with a Lotka-Volterra system. Suppose we modify those equations as follows: dA 3A(1 0.00025A) - 0.04AL dt dL -0.3L0.0004AL dt (a). Find the equilibrium solutions. Enter your answer as a list of ordered pairs (A, L), where A is the number of aphids and L the number of ladybugs. For example, if you found three equilibrium solutions, one with 100 aphids and 10 ladybugs, one with 200 aphids and 20 ladybugs, and one with 300 aphids and 30 ladybugs, you would enter (100, 10), (200, 20), (300, 30). Do not round fractional answers to the nearest integer. Answer =(0, 0), (2000,0), (750, 60.937) (b). Find an expression for dL/dA dL (-0.3L+0.0004AL/[3A(1-0.00025A)-0.04AL] dA

Answer 1

harc lotka -Valteror Lue dA 341-0.00025A) 004 AL dL -o.3L 0.o004 AL f equi ibrium Point AdL dt 3AC 1-0.00025A)- O.O4 AL O -D3L0.0004 AL a trom equahion Crd A = OSL Put it in 4- O000s O.04 xSoL X1501-0.0o025 X750 I2501-1875) O:04 X FO 60.9375 Now agaim it L=0 thn tron first enation 3/1-0.00025 A) So Au equilirigm ont wl k (0,0)50,60.9315) ned CamScanner

tnpranion fo d dt/du 0.3 L+0 0004AL cs Scanned with Cam S.canner