Question

(1 point) Populations of aphids and ladybugs are modeled by the equations - 1A – 0.01AL dA dt dL == -0.6L + 0.004AL dt (a). Find the equilibrium solutions. Enter your answer as a list of ordered pairs (A, L), where A is the number of aphids and L the number of ladybugs. For example, if you found three equilibrium solutions, one with 100 aphids and 10 ladybugs, one with 200 aphids and 20 ladybugs, and one with 300 aphids and 30 ladybugs, you would enter (100, 10), (200, 20), (300, 30). Do not round fractional answers to the nearest integer. Answer = (b). Find an expression for dL/dA. dL = dA

Answer 1

da dt LA -001 AL dl at -0.6L+0.004 AL a equilibrium solution- dA dt & de 0 -0 a le LA-001 AL=0 A(1-0.011) = 0 A=0 1-0.012=0 La 1 001 Loo -0.6L +0.004AL=0 ✓ L-01 -06L + 0.001 AL -0 1(-0.6 +0.00 4A): 0 Answer: (0,0), (150, 200) -0.6 +0.004 A = 0 600 0.004 4 A: 0.6 こ A=1sol

6 du da 0LF 0004AL L (-06 + 0.004A) di dt dA dt 1 1A - 001 AL AC 1-001) 우