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questions 35,36,37,38, and 39 all refer to the problem below In the reaction of iron (III)...

questions 35,36,37,38, and 39 all refer to the problem below

In the reaction of iron (III) sulfate and barium hydroxide,

Fe2(SO4)3 + 3Ba(OH)2 -> 3BaSO4 + 2Fe(OH)3.


If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2.

Molar masses

Fe2(SO4)3 = 399.91

Ba(OH)2 = 171.35

Fe(OH)3 = 106.88

35. How many moles of Fe(OH)3 will be produced if all 20.0 g of Fe2(SO4)3 were consumed?

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Answer #1

Fe, Coule + 3 Ba COH) a → 3 Basoy + 2 Fe(OH), Moles of Fe, (soya = Crinon mass Molen mans 2000g 3997.91g/mol = o.osoomot fromuse comment section for the doubts and clarifications

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