questions 35,36,37,38, and 39
all refer to the problem below
In the reaction of iron (III) sulfate and barium
hydroxide,
Fe2(SO4)3 + 3Ba(OH)2 -> 3BaSO4 + 2Fe(OH)3.
If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2.
Molar masses
Fe2(SO4)3 = 399.91
Ba(OH)2 = 171.35
Fe(OH)3 = 106.88
39. If one of the chem 10 students ran the reaction as stated in problem 35 and got 7.052 g of Ba(OH)2, what is the percentage yield for the reaction ?
35. How many moles of Fe(OH)3 will be produced if all 20.0 g of Fe2(SO4)3 were consumed? 0.100 mol (answer I think)
questions 35,36,37,38, and 39 all refer to the problem below In the reaction of iron (III)...
questions 35,36,37,38, and 39 all refer to the problem below In the reaction of iron (III) sulfate and barium hydroxide, Fe2(SO4)3 + 3Ba(OH)2 -> 3BaSO4 + 2Fe(OH)3. If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2. Molar masses Fe2(SO4)3 = 399.91 Ba(OH)2 = 171.35 Fe(OH)3 = 106.88 35. How many moles of Fe(OH)3 will be produced if all 20.0 g of Fe2(SO4)3 were consumed?
questions 35,36,37,38, and 39 all refer to the problem below In the reaction of iron (III) sulfate and barium hydroxide, Fe2(SO4)3 + 3Ba(OH)2 -> 3BaSO4 + 2Fe(OH)3. If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2. Molar masses Fe2(SO4)3 = 399.91 Ba(OH)2 = 171.35 Fe(OH)3 = 106.88 37. How many grams of Fe(OH)3 will be produced if both iron (III) sulfate and barium hydroxide were used in the reaction?
If one of my chem students ran the reaction, as stated in problem below, and got 7.052 g of Ba(OH)2, what is the percent yield of the reaction? iron (III) sulfate and barium hydroxide, Fe2(SO4)3 + 3Ba(OH)2 --> 3BaSO4 + 2Fe(OH)3 If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2. Molar masses: Fe2(SO4)3 =399.91 Ba(OH)2= 171.35 Fe(OH)3 = 106.88 How many moles of Fe(OH)3 will be produced if all 20.0 g of Fe2(SO4)3 were consumed?
In the reaction of iron (III) sulfate and barium hydroxide, Fe2(SO4)3 + 3Ba(OH)2 --> 3BaSO4 + 2Fe(OH)3 If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2. Molar masses: Fe2(SO4)3 =399.91 Ba(OH)2= 171.35 Fe(OH)3 = 106.88 How many moles of Fe(OH)3 will be produced if all 20.0 of Ba (OH)2 were consumed?
In the reaction of iron(III) sulfate and barium hydroxide, Fe2(SO4)3 + 3 Ba(OH)2 + 3BaSO4 + 2 Fe(OH)3 If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2, Molar Masses: Fe2(SO4)3 = 399.91 Ba(OH)2 = 171.35 Fe(OH)3 = 106.88 37. How many grams of Fe(OH)3 will be produced if both iron(III) sulfate and barium hydroxide were used in the reaction?
38. Referring to question 37, which reactant was the limiting reactant? In the reaction of iron(III) sulfate and barium hydroxide, Fe2(SO4)3 + 3 Ba(OH)2 ⟶ 3 BaSO4 + 2 Fe(OH)3 If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2 , Molar Masses: Fe2(SO4)3 = 399.91 Ba(OH)2 = 171.35 Fe(OH)3 = 106.88 37. How many grams of Fe(OH)3 will be produced if both iron(III) sulfate and barium hydroxide were used in the reaction? In the reaction of iron(III) sulfate and barium hydroxide, ...
In the reaction of iron(III) sulfate and barium hydroxide, Fe2(SO4)3 + 3 Ba(OH)2 - + 3 BaSO4 + 2 Fe(OH)3 If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2. Molar Masses: Fe2(SO4)3 = 399.91 Ba(OH)2 = 171.35 Fe(OH)3 = 106.88 35. How many moles of Fe(OH)3 will be produced if all 20.0 g of Fe2(SO4)3 were consumed?
Calculate the number of milliliters of 0.433 M
Ba(OH)2 required to precipitate all of
the Fe3+ ions in 156
mL of 0.487 M
Fe2(SO4)3
solution as Fe(OH)3. The equation for
the reaction is:
Fe2(SO4)3(aq) +
3Ba(OH)2(aq) 2Fe(OH)3(s)
+ 3BaSO4(aq)
_______ mL Ba(OH)2
Questions 40 and 41 all REFER TO THE PROBLEM BELOW! When chlorine gas is added to acetylene gas, liquid 1,1,2,2-tetrachloroethane is formed: 2 Cl2(g) + C2H2(g) ⟶ C2H2Cl4(l) 40. If 8.0 L of chlorine is reacted at STP, exactly how many liters of acetylene at STP would be needed to allow complete reaction? 39. If one of my Chem 10 students ran the reaction as stated in problems 35 and got 7.052 g of Ba(OH)2, what is the percent yield...
use the half reaction method to balance (SHOW ALL WORK) the following overall redox reaction describing the formation of acid mine drainage emanating from coal mines FeS2(s)+o2(g)+H2o(l)->FE(OH)3(s) +SO4 2-(aq) +H+(aq) balance redox entirely 1)FeS2+o2+h2o->fe2+ +So4 2- +h+ Balance redox entirely 2)2Fe2+ . + 1/2 O2 + 2H+ . ->2Fe3+ +H20 Balance this precipitation reaction Fe3+(aq) +3H2o(l) . -> F(OH)3 (s) +3H+(aq)