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Incorrect Question 39 0/2 pts 39. If one of my Chem 10 students ran the reaction as stated in problems 35 and got 7.052 g ofquestions 35,36,37,38, and 39 all refer to the problem below

In the reaction of iron (III) sulfate and barium hydroxide,

Fe2(SO4)3 + 3Ba(OH)2 -> 3BaSO4 + 2Fe(OH)3.


If 20.0 g of Fe2(SO4)3 is mixed with 20.0 g of Ba(OH)2.

Molar masses

Fe2(SO4)3 = 399.91

Ba(OH)2 = 171.35

Fe(OH)3 = 106.88

39. If one of the chem 10 students ran the reaction as stated in problem 35 and got 7.052 g of Ba(OH)2, what is the percentage yield for the reaction ?

35. How many moles of Fe(OH)3 will be produced if all 20.0 g of Fe2(SO4)3 were consumed? 0.100 mol (answer I think)

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Answer #1

04 399.9) Fez (504) + 3 Ba(OH)2 3 BaSO4 + 2 Fe(OH)3 Novo, Alearding to the above balanced equation, 1 mole of Fez (3641)3 rea

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